Physical electronics devices and ics miscellaneous

Physical electronics devices and ics miscellaneous

Easy Questions

Physical Electronics Devices and ICs

Physical electronics devices and ics miscellaneous
  1. In a transistor—








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    In a transistor emitter is very highly doped. Base is very lightly doped and collector is moderately doped, i.e. Doping profile: E > C > B.

    Correct Option: A

    In a transistor emitter is very highly doped. Base is very lightly doped and collector is moderately doped, i.e. Doping profile: E > C > B.

  1. The arrow on the emitter of a transistor indicates—








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    The arrow on the emitter of a transistor indicates the direction of conventional current flow.

    Correct Option: C

    The arrow on the emitter of a transistor indicates the direction of conventional current flow.

  1. The region of operation of the transistor in the circuit below is—










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    From given circuit (i.e., fig)
    VBE > 0 VCB < 0
    i.e. Both the junctions are forward biased.
    Hence transistor operating in saturation mode.


    Correct Option: C

    From given circuit (i.e., fig)
    VBE > 0 VCB < 0
    i.e. Both the junctions are forward biased.
    Hence transistor operating in saturation mode.


  1. The region of operation of the transistor in the circuit below is—










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    From given circuit (i.e., fig)
    VBE = 0
    VBC > 0
    Hence transistor operating in reverse-active mode


    Correct Option: B

    From given circuit (i.e., fig)
    VBE = 0
    VBC > 0
    Hence transistor operating in reverse-active mode


  1. For the circuit shown in figure the value of IC is Vin = 0.63V, Ib = 125µA, IC = 275µA—










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    Given: VBC > 0V
    IE = βR IB
    ∴ IE ≈ IC
    ∴ βR = IC IB = 275 µA 125 µA = 2.2
    αR = βR βR + 1 = 2.2 2.2 + 1 = 0.6875
    IE ≈ IC = IC αR = 275 0·6875 ≈ 400mA

    Correct Option: B

    Given: VBC > 0V
    IE = βR IB
    ∴ IE ≈ IC
    ∴ βR = IC IB = 275 µA 125 µA = 2.2
    αR = βR βR + 1 = 2.2 2.2 + 1 = 0.6875
    IE ≈ IC = IC αR = 275 0·6875 ≈ 400mA