Physical electronics devices and ics miscellaneous
- The beta (β) of a transistor may be determined directly from the plots of—
-
View Hint View Answer Discuss in Forum
The gain of transistor i.e., β may be determined directly from the VCE versus i C plot for constant values of IB.
Correct Option: C
The gain of transistor i.e., β may be determined directly from the VCE versus i C plot for constant values of IB.
- The JFET in the circuit shown in figure has an IDSS = 10 mA and Vp = – 5 V. The value of the resistance RS for a drain current IDS = 6.4 mA is (select the nearest value)—
-
View Hint View Answer Discuss in Forum
We know that
IDS = IDSS 1 - VGS …(a) VP
given that, IDS = 6.4 × 10– 3 amp
VP = – 5 V
IDSS = 10 × 10– 3 amp. VGS =?6.4 × 10– 3 = 10 × 10– 3 1 - VGS 2 - 5 1 – VGS = √64 = .8 - 5
or VGS = – 1V
Now, IDS RS = – VGS = – (– 1 V)RS = 1 = 156 6.4 × 10–3
Since 156 Ω is very close to 150 Ω.
Hence alternative (A) is correct answer.Correct Option: A
We know that
IDS = IDSS 1 - VGS …(a) VP
given that, IDS = 6.4 × 10– 3 amp
VP = – 5 V
IDSS = 10 × 10– 3 amp. VGS =?6.4 × 10– 3 = 10 × 10– 3 1 - VGS 2 - 5 1 – VGS = √64 = .8 - 5
or VGS = – 1V
Now, IDS RS = – VGS = – (– 1 V)RS = 1 = 156 6.4 × 10–3
Since 156 Ω is very close to 150 Ω.
Hence alternative (A) is correct answer.
- The light-emitting diode (LED)—
-
View Hint View Answer Discuss in Forum
The basic phenomenon of light emitting diode (LED) depends on the recombination of holes and electrons.
Correct Option: D
The basic phenomenon of light emitting diode (LED) depends on the recombination of holes and electrons.
- A zener diode—
-
View Hint View Answer Discuss in Forum
A zener diode has a sharp breakdown at low reverse voltage.
Correct Option: B
A zener diode has a sharp breakdown at low reverse voltage.
- In a Schmitt trigger using OP amplifiers the output is limited by diode clipper to V0 = ± 8 volts. The positive input terminal voltage V+ = β V0, where β = 1 / 8. The signal Vs is applied to V–.
The following statements (1) to (4) are made regarding Vs and V+
(1) For Vs negative and rising V+ = + 1
(2) For Vs positive and decreasing V+ = + 1
(3) For Vs decreasing through zero value V+ = + 1
(4) For Vs increasing though zero value V+ = + 1
Of these statements, the true statements are—
-
View Hint View Answer Discuss in Forum
NA
Correct Option: C
NA