Physical electronics devices and ics miscellaneous

Physical electronics devices and ics miscellaneous

Easy Questions

Physical Electronics Devices and ICs

Physical electronics devices and ics miscellaneous
  1. Determine ID2.—










  1. View Hint View Answer Discuss in Forum

    From the given information, we can make the equivalent circuit as shown below:
    From above circuit
    ID = ID1 + ID2 (Also = ID1 = ID2)

    ID =
    (10 – 0.3) V
    		= 29.40 mA
    0.33 kΩ

    and ID2 =
    ID
    		=
    29.40
    		mA = 14.70 mA
    22

    and ID1 =
    ID
    		=
    29.40
    		mA = 14.70 mA
    22


    Correct Option: C

    From the given information, we can make the equivalent circuit as shown below:
    From above circuit
    ID = ID1 + ID2 (Also = ID1 = ID2)

    ID =
    (10 – 0.3) V
    		= 29.40 mA
    0.33 kΩ

    and ID2 =
    ID
    		=
    29.40
    		mA = 14.70 mA
    22

    and ID1 =
    ID
    		=
    29.40
    		mA = 14.70 mA
    22


  1. Determine ID1.—










  1. View Hint View Answer Discuss in Forum

    Here, Ge diode ‘ON’ preventing Si diode from turning ‘ON’ as shown below in figure
    Therefore, ID1 = 0 mA Hence alternative (A) is the correct choice.


    Correct Option: A

    Here, Ge diode ‘ON’ preventing Si diode from turning ‘ON’ as shown below in figure
    Therefore, ID1 = 0 mA Hence alternative (A) is the correct choice.


  1. Determine ID2.—










  1. View Hint View Answer Discuss in Forum

    From the given information, we can make the equivalent circuit as shown below:
    From the above circuit KVL in loop 1
    20–0.7 –0.3–5.6 kΩ × ID1 = 0

    ID1 =
    19 V
    		= 3.393 mA
    5.6 kΩ

    and I3kΩ =
    0.3 V
    		= 0.09 mA
    3.3 kΩ

    So, ID2 = ID1 – I3kΩ = 3.303 mA


    Correct Option: D

    From the given information, we can make the equivalent circuit as shown below:
    From the above circuit KVL in loop 1
    20–0.7 –0.3–5.6 kΩ × ID1 = 0

    ID1 =
    19 V
    		= 3.393 mA
    5.6 kΩ

    and I3kΩ =
    0.3 V
    		= 0.09 mA
    3.3 kΩ

    So, ID2 = ID1 – I3kΩ = 3.303 mA


  1. Determine the current through each diode if E1 = E2 = 0V.—










  1. View Hint View Answer Discuss in Forum

    From the given information we can make the equivalent circuit as shown below:
    From below (i.e., fig-2) figure current through each diode

    I =
    10 - 0.7
    		= 9.3 mA
    1 kΩ


    Correct Option: B

    From the given information we can make the equivalent circuit as shown below:
    From below (i.e., fig-2) figure current through each diode

    I =
    10 - 0.7
    		= 9.3 mA
    1 kΩ


  1. Determine Vo if E1 = E2 = 10V—










  1. View Hint View Answer Discuss in Forum

    From the given information we can make the equivalent circuit as shown below:
    Both the diodes are open circuited due to reverse bias. It means there is no current in the circuit and there is no voltage drop in 1 kΩ resistance. Therefore, V0 = 10 V


    Correct Option: B

    From the given information we can make the equivalent circuit as shown below:
    Both the diodes are open circuited due to reverse bias. It means there is no current in the circuit and there is no voltage drop in 1 kΩ resistance. Therefore, V0 = 10 V