Physical electronics devices and ics miscellaneous


Physical electronics devices and ics miscellaneous

Physical Electronics Devices and ICs

  1. Under high electric fields, in a semiconductor increasing electric field—
    1. Mobility decreases
    2. Mobility increases
    3. Velocity saturates
    4. Velocity increases The correct statements are:









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    Under high electric fields, in a semiconductor increasing electric field—
    ● Mobility decreases
    ● Velocity saturates

    Correct Option: B

    Under high electric fields, in a semiconductor increasing electric field—
    ● Mobility decreases
    ● Velocity saturates


  1. The ratio of diffusion constant to mobility of carriers—









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    We know that
    Dn
    =
    KT
    = VT
    µnq

    The ratio of diffusion constant to mobility is depends on temperature.

    Correct Option: A

    We know that
    Dn
    =
    KT
    = VT
    µnq

    The ratio of diffusion constant to mobility is depends on temperature.



  1. A Clipper circuit always—









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    A primary function of clamper circuit is to introduce a dc level into an ac level.

    Correct Option: D

    A primary function of clamper circuit is to introduce a dc level into an ac level.


  1. Pure Si is experimentally determined to exhibit a carrier (electron or hole) density of 1·48 × 1010 electrons (holes) cm3 at 300° K. If the electron mobility and hole mobility is 1300 cm2/Vs and 500 cm2/Vs, the resistivity of an intrinsic Si specimen at 300 °K is …………?









  1. View Hint View Answer Discuss in Forum

    Given
    µi = 1·48 × 1010 cm3
    µn = 1300 cm2/V–s
    µp = 500 cm2/V–s
    i =?


    We know that, i =
    1
    =
    1
    i q nin + µp)

    or i =
    1
    1·6 × 10–19 × 1·48 × 1010 (1300 + 500)

    or i = 2·35 × 105 Ω–cm
    Hence alternative (C) is the correct choice.

    Correct Option: C

    Given
    µi = 1·48 × 1010 cm3
    µn = 1300 cm2/V–s
    µp = 500 cm2/V–s
    i =?


    We know that, i =
    1
    =
    1
    i q nin + µp)

    or i =
    1
    1·6 × 10–19 × 1·48 × 1010 (1300 + 500)

    or i = 2·35 × 105 Ω–cm
    Hence alternative (C) is the correct choice.



  1. Bridge rectifiers are preferred because—









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    Bridge rectifiers are preferred because
    * They require small transformer, and
    * Less peak inverse voltage

    Correct Option: C

    Bridge rectifiers are preferred because
    * They require small transformer, and
    * Less peak inverse voltage