For the circuit shown in figure the value of IC is Vin =

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For the circuit shown in figure the value of I_C is V_in = 0.63V, I_b = 125µA, I_C = 275µA—

1. 400 µA
2. 400 µA
3. 600 µA
4. 600 µA

Correct Option: B

Given: V_BC > 0V
I_E = β_R I_B
∴ I_E ≈ I_C
∴ β_R = I_C I_B = 275 µA 125 µA = 2.2
α_R = β_R β_R + 1 = 2.2 2.2 + 1 = 0.6875
I_E ≈ I_C = I_C α_R = 275 0·6875 ≈ 400mA