401. In an FET—

1. 1. Both the junction are reverse biased

   
   
   

   2. One junction is reverse biased and the other forward biased

   
   
   

   3. One junction has reverse bias on both side of the junction

   
   
   

   4. One junction has reverse bias on side and forward bias on the other
      

   
   
   

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1. View Hint View Answer Discuss in Forum

   In an FET are junction has reverse bias on both side of the junction.

   Correct Option: C

   In an FET are junction has reverse bias on both side of the junction.

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402. The common-emitter input volt-ampere characteristic may be shown by plots of—

1. 1. V_CB versus i _C for constant values of I_E

   
   
   

   2. V_CE versus i _C for constant values of I_B

   
   
   

   3. V_CF versus i _E for constant values of V_ES

   
   
   

   4. V_BE versus i_B for constant values of V_CE
      

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: B

   NA

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403. The current I_CEO is—

1. 1. The collector current in the common-emitter connected transistor with zero base current

   
   
   

   2. The emitter current in the common-collected transistor with zero base current

   
   
   

   3. The collector current in the common-emitter connected transistor with zero emitter current

   
   
   

   4. The same as I_CBO
      

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: D

   NA

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404. In CB configuration, the output volt-ampere characteristics of the transistor may be shown by plots of—

1. 1. V_CB versus i _C for constant values of I_F

   
   
   

   2. V_CB versus i _B for constant values of I_E

   
   
   

   3. V_CB versus i _E for constant values of I_B

   
   
   

   4. V_CB versus i _C for constant values of I_B
      

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: D

   NA

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405. The 6 V zener diode shown in figure has zero zener resistance and a knee current of 5 mA. The minimum value of R so that voltage across it does not fall below 6 V is—
     
     
     

1. 1. 1.2 kΩ

   
   
   

   2. 80 Ω

   
   
   

   3. 50 Ω

   
   
   

   4. 0 Ω

   
   
   

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1. View Hint View Answer Discuss in Forum

   Given that I_Z (knee current) = 5 mA
   
   

   I =		10 - 6	=	4
   		50		50

   
   I = 80 mA
   I_R = I – I_Z = 80 – 5 = 75 mA
   

   R =		V	=	6	=	6000	= 80 Ω.
   		IR		75 x 10-3		75

   
   Hence alternative (B) is the correct answer.

   Correct Option: B

   Given that I_Z (knee current) = 5 mA
   
   

   I =		10 - 6	=	4
   		50		50

   
   I = 80 mA
   I_R = I – I_Z = 80 – 5 = 75 mA
   

   R =		V	=	6	=	6000	= 80 Ω.
   		IR		75 x 10-3		75

   
   Hence alternative (B) is the correct answer.

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