Materials Science and Manufacturing Engineering Miscellaneous


Materials Science and Manufacturing Engineering Miscellaneous

Materials Science and Manufacturing Engineering

  1. Two 8 mm thick steel plates are placed 5 mm apart and welded by a butt joint. Welding is carried out at 20 V and speed of 5 mm/s. Heat transfer efficiency is 0.80. If the heat required to melt steel is 10 J/mm3 and melting efficiency is 0.625. The weld current (in amperes) will be









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    t = 8 mm, Gap = 5mm
    V = 20 volts, v = 5 mm/s
    ηHt = 0.8, H = 10J/mm, ηm = 0.625
    I =?
    Volume of weld pool = 8 × 5 × x
    = 40 x mm3
    Heat Required = 10 × 40 x = 400 x J
    Heat Generated

    = ηHtηm
    VIx
    v

    = 400=
    0.625 × 20 × I × x × 0.8
    5

    I = 200 A

    Correct Option: B

    t = 8 mm, Gap = 5mm
    V = 20 volts, v = 5 mm/s
    ηHt = 0.8, H = 10J/mm, ηm = 0.625
    I =?
    Volume of weld pool = 8 × 5 × x
    = 40 x mm3
    Heat Required = 10 × 40 x = 400 x J
    Heat Generated

    = ηHtηm
    VIx
    v

    = 400=
    0.625 × 20 × I × x × 0.8
    5

    I = 200 A


  1. In a fabrication shop, a T-joint is to be made between two plates using a chin intermittent, double fillet weld of 6 mm leg length. The intermittent welds are 40 mm long and spaced 80 mm apart, edge to edge. The welding symbol of the joint is









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    Correct Option: D



  1. The metal powder used in Thermit welding of steel is









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    Exothermic Reaction
    3Fe3 04 + 8Al → 9Fe + 4 Al2 03 + Heat

    Correct Option: A

    Exothermic Reaction
    3Fe3 04 + 8Al → 9Fe + 4 Al2 03 + Heat


  1. A 900 mm long steel plate is welded by manual metal arc welding process using welding current of 150 A, arc voltage of 20 V and welding speed of 300 mm/min. If the process efficiency of is 0.8 and surface resistance is 36 micro-ohm, the heat input in J/mm









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    Heat Input to weld

    = η
    VI
    =
    0.8 × 20 × 150
    = 480 J/mm.
    V300/60

    Correct Option: B

    Heat Input to weld

    = η
    VI
    =
    0.8 × 20 × 150
    = 480 J/mm.
    V300/60



  1. A cup of 10 cm height and 5 cm diameter is to be made from a sheet metal of 2 mm thickness. The number of deductions necessary will be









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    D = √d2 + 4hd = √52 + 4 × 5 × 10 = 15 cm
    first reduction 50%
    Next reduction 30%

    Correct Option: C

    D = √d2 + 4hd = √52 + 4 × 5 × 10 = 15 cm
    first reduction 50%
    Next reduction 30%