Materials Science and Manufacturing Engineering Miscellaneous


Materials Science and Manufacturing Engineering Miscellaneous

Materials Science and Manufacturing Engineering

  1. The tool life equation for HSS tool is VT0.14f0.7d0.4 = Constant. The tool life (T) of 30 min is obtained using the following cutting conditions: V= 45 m/min, f = 0.35 mm, d =2.0 mm. If speed (V), feed (f) and depth of cut (d) are increased individually by 25%, the tool life (in min) is









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    VT0.14 f 0.7 d0.4 = C
    ⇒ T1 =30 min,
    V1 =45 m/min,
    f1 =0.35 min,
    d1 =2.0 mm,
    ⇒ C =V1 (T1) 0.14 (f1) 0.7 (d1) 0.4
    C =45(30)0.14 (0.35)0.7 (2)0.4
    C =45.8425
    V2 (T2) 0.14 (f 2) 0.7 (d2) 0.4 = 45.8425
    (1.25 × 45)(T2) 0.14 (1.25 × 0.35)0.7 (1.25 × 2)0.4
    = 45.8425
    ⇒ T2 =1.06 min

    Correct Option: B

    VT0.14 f 0.7 d0.4 = C
    ⇒ T1 =30 min,
    V1 =45 m/min,
    f1 =0.35 min,
    d1 =2.0 mm,
    ⇒ C =V1 (T1) 0.14 (f1) 0.7 (d1) 0.4
    C =45(30)0.14 (0.35)0.7 (2)0.4
    C =45.8425
    V2 (T2) 0.14 (f 2) 0.7 (d2) 0.4 = 45.8425
    (1.25 × 45)(T2) 0.14 (1.25 × 0.35)0.7 (1.25 × 2)0.4
    = 45.8425
    ⇒ T2 =1.06 min


  1. In an orthogonal cutting process the tool used has rake angle of zero degree. The measured cutting force and thrust force are 500 N and 250 N, respectively. The coefficient of friction between the tool and the chip is









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    Because the rake angle is zero,
    F = Friction force = Fc = Cutting force = 500 N,
    N = normal to friction force = Ft = thrust force = 250 N,
    Coefficient of friction = F/N = 250/500 = 0.5

    Correct Option: C

    Because the rake angle is zero,
    F = Friction force = Fc = Cutting force = 500 N,
    N = normal to friction force = Ft = thrust force = 250 N,
    Coefficient of friction = F/N = 250/500 = 0.5



  1. A shaft of length 90 mm has a tapered portion of length 55 mm. The diameter of the taper is 80 mm at one end and 65 mm at the other. If the taper is made by tail stock set over method, the taper angle and the set over respectively are









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    Rate of taper,

    T =
    80 - 65
    = 0.27
    55

    Set over =
    T × L
    =
    0.27 × 90
    = 12.15
    22

    Correct Option: A

    Rate of taper,

    T =
    80 - 65
    = 0.27
    55

    Set over =
    T × L
    =
    0.27 × 90
    = 12.15
    22


  1. Orthogonal turning of a mild steel tube with a tool of rake angle 10° carried out at a feed of 0.14 mm/rev. If the thickness of the chip produced is 0.28 mm, the values of shear angle and shear strain will be respectively









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    r =
    0.14
    = 0.5
    0.28

    tanΦ =
    r cos α
    1 - rsin α

    ∴ Φ = 28.3345º or 28º 20'

    Correct Option: A

    r =
    0.14
    = 0.5
    0.28

    tanΦ =
    r cos α
    1 - rsin α

    ∴ Φ = 28.3345º or 28º 20'



  1. In a machining operation, if the generatrix and directrix both are straight lines, the surface obtained is









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    The surface obtained is plane.

    Correct Option: C

    The surface obtained is plane.