Materials Science and Manufacturing Engineering Miscellaneous

Materials Science and Manufacturing Engineering Miscellaneous

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Materials Science and Manufacturing Engineering

Materials Science and Manufacturing Engineering Miscellaneous
  1. The combination of slip gauges to obtain a dimension of 10.35 mm will be








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    Normally, slip gauge box set does not have slip of less than 1 mm thickness. Always use minimum number of slipgauges in combination & less than 1mm thickness is not in set.

    Correct Option: B

    Normally, slip gauge box set does not have slip of less than 1 mm thickness. Always use minimum number of slipgauges in combination & less than 1mm thickness is not in set.

  1. Outside diameter of bush is turned using a mandrel. The mandrel diameter is maintained as 0.000 0.050 30.000−0.0500.000 mm and the bore diameter is 30.000−0.0000.050 mm. The maximum value in mm of the eccentricity on the bush due to the locating mandrel








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    Maximum size of Bore = 30.050mm
    Minimum size of Mandrel = 29.95mm
    Diametral Gap = 0.1mm

    Eccentricity =
    0.1
    		= 0.05 mm
    2

    Correct Option: A

    Maximum size of Bore = 30.050mm
    Minimum size of Mandrel = 29.95mm
    Diametral Gap = 0.1mm

    Eccentricity =
    0.1
    		= 0.05 mm
    2

  1. The most common limit gauge used for inspecting the hole diameter is








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    Plug gauge is a cylindrical type of gauge, used to check the accuracy of holes.

    Correct Option: A

    Plug gauge is a cylindrical type of gauge, used to check the accuracy of holes.

  1. A circular shaft having diameter 65.00−0.015+0.01 mm is manufactur ed by turning pr ocess. A 50 m t hi ck coat i ng of Ti N i s deposited on the shaft Allowed variation in TiN film thickness is ±5 m. The minimum hole diameter (in mm) to just provide clearance fit is








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    Shaft = 65−0.05+0.01 mm
    Coating thickness ‘t’ = (50 ± 5)μm
    To provide clearance fit, given condition should be satisfied,
    (DH)min ≥ ((D)shaft)max ≥(Ds )max + 2tmax

    = 65.01 +
    2 × 55
    		= 65.12mm
    1000

    Correct Option: C

    Shaft = 65−0.05+0.01 mm
    Coating thickness ‘t’ = (50 ± 5)μm
    To provide clearance fit, given condition should be satisfied,
    (DH)min ≥ ((D)shaft)max ≥(Ds )max + 2tmax

    = 65.01 +
    2 × 55
    		= 65.12mm
    1000

  1. The height (in mm) for a 125 mm sine bar to 'measure a taper of 27'32' on a flat work piece is _________(correct to three decimal places).








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    θ = 27°32' = 27 +
    32
    		° = 27.533°
    60

    In sine bar, sin θ =
    H
    L

    sin 27.533° =
    H
    125

    H = 57.782427
    H ≈ 57.782 mm

    Correct Option: A

    θ = 27°32' = 27 +
    32
    		° = 27.533°
    60

    In sine bar, sin θ =
    H
    L

    sin 27.533° =
    H
    125

    H = 57.782427
    H ≈ 57.782 mm