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Two 8 mm thick steel plates are placed 5 mm apart and welded by a butt joint. Welding is carried out at 20 V and speed of 5 mm/s. Heat transfer efficiency is 0.80. If the heat required to melt steel is 10 J/mm3 and melting efficiency is 0.625. The weld current (in amperes) will be
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- 100
- 200
- 300
- 400
Correct Option: B
t = 8 mm, Gap = 5mm
V = 20 volts, v = 5 mm/s
ηHt = 0.8, H = 10J/mm, ηm = 0.625
I =?
Volume of weld pool = 8 × 5 × x
= 40 x mm3
Heat Required = 10 × 40 x = 400 x J
Heat Generated
= ηHtηm | v |
= 400= | 5 |
I = 200 A