Materials Science and Manufacturing Engineering Miscellaneous
- A metal disc of 20 mm diameter is to be punched from a sheet of 2 mm thickness. The punch and the dia clearance is 3%. The required punch diameter is
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Punch diameter = 20 – 2 × 3% of thickness
Punch diameter = 20 – 2 × 3 × 2 = 20 - 0.12 = 19.88 mm 100 Thickness of blank = 1.5 = 3 mm cos60° Correct Option: A
Punch diameter = 20 – 2 × 3% of thickness
Punch diameter = 20 – 2 × 3 × 2 = 20 - 0.12 = 19.88 mm 100 Thickness of blank = 1.5 = 3 mm cos60°
- In blanking operation the clearance is provided on
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Blanking operation cleanness is provided on. Punch Die will be exact.
Correct Option: B
Blanking operation cleanness is provided on. Punch Die will be exact.
- The cutting force in punching and blanking operations mainly depends on
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Cutting force = τ × A
τ = Shear strengthCorrect Option: B
Cutting force = τ × A
τ = Shear strength
- A 50 mm diameter disc is to be punched out from a carbon steel sheet 1.0 mm thick. The diameter of the die should be (Take clearance as 3% of sheet thickness) _______.
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Clearness should be given on punch in Blanking operation. Die should be exact.
Correct Option: B
Clearness should be given on punch in Blanking operation. Die should be exact.
- The thickness of the blank needed to produce, by power spinning a missile cone of thickness 1.5 mm and half cone angle 30°
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Thickness of blank = cone thickness cos( 2α ) Thickness of blank = 1.5 = 3 mm cos60° Correct Option: A
Thickness of blank = cone thickness cos( 2α ) Thickness of blank = 1.5 = 3 mm cos60°