Materials Science and Manufacturing Engineering Miscellaneous
- During a TIG welding process, the arc current and arc voltage were 50 A and 60 V, respectively, when the welding speed was 150 mm/min. In another process, the TIG welding is carried out at a welding speed of 120 mm/min at the same arc voltage and heat input to the material so that weld quality remains the same. The welding current (in A) for this process is ___________
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Total heat input = VIt
Time t is inversely proportional to weld speed (S)∴ V2I2 = V1I1 S2 S1 ∴ I2 = 120 × 50 150
I2 = 40ACorrect Option: A
Total heat input = VIt
Time t is inversely proportional to weld speed (S)∴ V2I2 = V1I1 S2 S1 ∴ I2 = 120 × 50 150
I2 = 40A
- A DC welding power source has a linear voltagecurrent (V-I) characteristic with open circuit voltage of 80 V and a short circuit current of 300 A. For maximum arc power, the current (in Ampere) should be set as______.
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Constant Voltage characteristics
150A = vocV − vocV I 1scc V = 80 − 80 I 300
P = V I= 80 − 80 I I 300
For Maximum PowerdP = 0 dI
80 – 2 × 0.666 I = 0
I = 150ACorrect Option: A
Constant Voltage characteristics
150A = vocV − vocV I 1scc V = 80 − 80 I 300
P = V I= 80 − 80 I I 300
For Maximum PowerdP = 0 dI
80 – 2 × 0.666 I = 0
I = 150A
- In a linear arc welding process, the heat input per unit length is inversely proportional to
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Heat Input = Voltage × current welding speed SoHeat Input ∝ 1 welding speed Correct Option: C
Heat Input = Voltage × current welding speed SoHeat Input ∝ 1 welding speed
- In a DC arc welding operation, the voltage-arc length characteristic was obtained as Varc = 20 + 5l where the arc length l was varied between 5 mm and 7 mm. Here Varc denotes the arc voltage in Volts. The arc current was varied from 400 A to 500 A. Assuming linear power source characteristic, the open circuit voltage and the short circuit current for the welding operation are
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Var = 20 + 5l
For l = 5 mm, Varc = 45 V
For l = 7 mm, Varc = 55VV = V0 − V0 I IS
where Vo is open circuit voltage and IS is short circuit current.∴ 45 = V0 − V0 × 500 IS and 55 = V0 − V0 × 400 IS
By solving, we get
V0 = 95 Volts
IS = 950 ACorrect Option: C
Var = 20 + 5l
For l = 5 mm, Varc = 45 V
For l = 7 mm, Varc = 55VV = V0 − V0 I IS
where Vo is open circuit voltage and IS is short circuit current.∴ 45 = V0 − V0 × 500 IS and 55 = V0 − V0 × 400 IS
By solving, we get
V0 = 95 Volts
IS = 950 A
- Which one among the following welding processes uses non-consumable electrode?
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Tungsten Electrode is used to create arc only. Reverse polarity is used to weld Aluminium metal.
Correct Option: C
Tungsten Electrode is used to create arc only. Reverse polarity is used to weld Aluminium metal.