Materials Science and Manufacturing Engineering Miscellaneous


Materials Science and Manufacturing Engineering Miscellaneous

Materials Science and Manufacturing Engineering

  1. In a grinding wheel marked with AA-48-L-7-V- 25, L refers to









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    Correct Option: C


  1. A drilling machine has to be designed with 8 spindle speeds ranging approximately between 120 to 1200 rpm. The 5th spindle speed is









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    Nmin = 120 Nmax = 1200
    N = 8

    N5 = N1 r4 = 120 × 1.3844
    N = 447rpm

    Correct Option: A

    Nmin = 120 Nmax = 1200
    N = 8

    N5 = N1 r4 = 120 × 1.3844
    N = 447rpm



  1. Assertion (A): Single start threads are used for fastening purposes.
    Reason (R): Single start threads are easier to produce in a lathe.









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    Single start thread on be made by single point cutting tool.

    Correct Option: B

    Single start thread on be made by single point cutting tool.


  1. A through hole is drilled in an aluminium alloy plate of 15 mm thickness with a drill bit of diameter 10 mm, at a feed of 0.25 mm/rev and a spindle speed of 1200 rpm. If the specific energy required for cutting this material is 0.7 N-m/ mm3, the power required for drilling is ___ W (round off to two decimal places).









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    Power required, P = S × Q
    Where S = specific power = 0.7 N-m/mm3

    Q = MRR =
    π D2
    × f × N
    4

    =
    π × (10)2
    × 0.25 ×
    1200
    = 125π mm3/sec
    460

    Power, P = 0.7 × 125π
    P = 274.889 W ≈ 274.89 W

    Correct Option: A

    Power required, P = S × Q
    Where S = specific power = 0.7 N-m/mm3

    Q = MRR =
    π D2
    × f × N
    4

    =
    π × (10)2
    × 0.25 ×
    1200
    = 125π mm3/sec
    460

    Power, P = 0.7 × 125π
    P = 274.889 W ≈ 274.89 W



  1. The length, width and thickness of a steel sample are 400 mm, 410 mm, 40 mm and 20 mm, respectively. I ts thickness needs to be uniformly reduced by 2 mm in a single pass by using horizontal slab miling. The miling cutter (diameter: 100 mm, width; 50 mm) has 20 teeth and rotates at 1200 rpm. The feed per tooth is 0.05 mm. The feed direction is along the length of the sample. If the over-travel distance is the same as the approach distance, the approach distance and time taken to complete t he required machining task are:









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    Depth of cut ⇒ (d = 2 mm) Milling cutter,
    D = 100 mm
    W = 50 mm
    Z = 20 tooth,
    N = 1200 rpm
    ft = 0.05 mm/tooth rev
    f = z × ft = 20 × 0.05 mm/rev
    = 1 mm/rev
    Over travel = Approach (A)
    = √d(D - d)
    = √2 × (100 - 2)
    = √196 = 14 mm
    Total length covered by tool
    L + 2A = 400 + 2 × 14 = 428 mm
    Time for one pass,

    t =
    L
    fN

    =428
    1 ×
    1200
    60

    =
    428
    = 21.4 second
    20

    Correct Option: C


    Depth of cut ⇒ (d = 2 mm) Milling cutter,
    D = 100 mm
    W = 50 mm
    Z = 20 tooth,
    N = 1200 rpm
    ft = 0.05 mm/tooth rev
    f = z × ft = 20 × 0.05 mm/rev
    = 1 mm/rev
    Over travel = Approach (A)
    = √d(D - d)
    = √2 × (100 - 2)
    = √196 = 14 mm
    Total length covered by tool
    L + 2A = 400 + 2 × 14 = 428 mm
    Time for one pass,

    t =
    L
    fN

    =428
    1 ×
    1200
    60

    =
    428
    = 21.4 second
    20