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In an orthogonal cutting process the tool used has rake angle of zero degree. The measured cutting force and thrust force are 500 N and 250 N, respectively. The coefficient of friction between the tool and the chip is
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- 0.7
- 0.6
- 0.5
- 0.9
Correct Option: C
Because the rake angle is zero,
F = Friction force = Fc = Cutting force = 500 N,
N = normal to friction force = Ft = thrust force = 250 N,
Coefficient of friction = F/N = 250/500 = 0.5