6. An elastic body is subjected to a tensile stress X in a particular direction and a compressive stress Y in its perpendicular direction. X and Y are unequal in magnitude. On the plane of maximum shear stress in the body there will be
   

1. 1. no normal stress
      

   
   
   

   2. also the maximum normal stress
      

   
   
   

   3. the minimum normal stress
      

   
   
   

   4. both normal stress and shear stress

   
   
   

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   NA

   Correct Option: C

   NA

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7. A rod of length 20 mm is stretched to make a rod of length 40 mm. Subsequently, it is compressed to make a rod of final length 10 mm. Consider the longitudinal tensile strain as positive and compressive strain as negative. The total true longitudinal strain in the rod is
   

1. 1. –0.5
      

   
   
   

   2. –0.69
      

   
   
   

   3. –0.75
      

   
   
   

   4. –1.0

   
   
   

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   Volume remain same L₁ = 20 mm, L₂ = 40 mm, L₃ = 10mm
   A₁ L₁ = A₂ L₂ = A₃ L₃
   

   	A1	=	L3
   	A3		L1

   
   

   True strain = ln		A1		= ln		L3		= -0.693
   		A3				L1

   
   

   Correct Option: B

   Volume remain same L₁ = 20 mm, L₂ = 40 mm, L₃ = 10mm
   A₁ L₁ = A₂ L₂ = A₃ L₃
   

   	A1	=	L3
   	A3		L1

   
   

   True strain = ln		A1		= ln		L3		= -0.693
   		A3				L1

   
   

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8. A rod of length L having uniform cross-section area A is subjected to a tensile force P as shown in the figure below. If the Young's modulus of the material varies linearly from E₁ to E₂ along the length of the rod, the normal stress developed at the section-SS at
   
   

1. 1. P

      A

      
      

   
   
   

   2. P(E1 - E2)

      A(E1 - E2)

      
      

   
   
   

   3. PE2

      AE1

      
      

   
   
   

   4. PE1

      AE2

   
   
   

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   At section 55 : -
   The left side of rod
   
   

   Normal stress σn =	R	=	P
   	A		A

   
   
   

   	∴	∑Fx = 0 ,
   			R - P = 0

   
   
   ∑F_x = 0
   ⇒ R₂ - P = 0
   ⇒ R₂ = P
   

   Normal stress σn =	P2	=	P
   	A		A

   
   

   ∴ Hence normal =	P
   	A

   
   

   Correct Option: A

   At section 55 : -
   The left side of rod
   
   

   Normal stress σn =	R	=	P
   	A		A

   
   
   

   	∴	∑Fx = 0 ,
   			R - P = 0

   
   
   ∑F_x = 0
   ⇒ R₂ - P = 0
   ⇒ R₂ = P
   

   Normal stress σn =	P2	=	P
   	A		A

   
   

   ∴ Hence normal =	P
   	A

   
   

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9. A thin plate of uniform thickness is subject to pressure as shown in the figure below
   
   Under the assumption of plane stress, which one of the following is correct?
   

1. 1. Normal stress is zero in the z-direction
      

   
   
   

   2. Normal stress is tensile in the z-direction
      

   
   
   

   3. Normal stress is compressive in the z - direction
      

   
   
   

   4. Normal stress varies in the z-direction

   
   
   

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   For a plane stress criteria.
   Normal stress in Z direction = 0.

   Correct Option: A

   For a plane stress criteria.
   Normal stress in Z direction = 0.

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10. The stress-strain curve for mild steel is shown in figure given below. Choose the correct option referring to both figure and table.
    
    
    
    

1. 1. P–1, Q–2, R–3, S–4, T–5, U–6
      

   
   
   

   2. P–3, Q–1, R–4, S–2, T–6, U–5
      

   
   
   

   3. P–3, Q–4, R–1, S–5, T–2, U–6
      

   
   
   

   4. P–4, Q–1, R–5, S–2, T–3, U–6

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   NA

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