Strength Of Materials Miscellaneous


Strength Of Materials Miscellaneous

Strength Of Materials

  1. Consider a cantilever beam, having negligible mass and uniform flexural rigidity, with length 0.01 m. The frequency of vibration of the beam, with a 0.5 kg mass attached at the free tip, is 100 Hz. The flexural rigidity (in Nm2) of the beam is ______.









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    S =
    FL3
    3EI

    k =
    F
    3EI
    SL3

    k =
    3EI
    (0.01)3

    k = 3, 000, 000 EI

    Correct Option: A

    S =
    FL3
    3EI

    k =
    F
    3EI
    SL3

    k =
    3EI
    (0.01)3

    k = 3, 000, 000 EI


  1. A cantilever beam carries the anti symmetric load shown, where W0 is the peak intensity of the distributed load. Qualitatively, the correct bending moment diagram for this beam is









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    Here at both the ends, slope is zero and SF is zero. As moving form left to right, rate of shear force decreases due to varying uniform distributed load.

    Correct Option: C


    Here at both the ends, slope is zero and SF is zero. As moving form left to right, rate of shear force decreases due to varying uniform distributed load.



Direction: A steel beam of breadth 120 mm and height 750 mm is loaded as shown in the figure. Assume Esteel = 200 GPa.

  1. The value of maximum deflection of the beam is









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    Moment of inertia

    I =
    bh3
    =
    120 × (750)3
    = 42.1875 × 108 mm4
    1212

    Maximum deflection in the beam is given by
    δ =
    5
    wL4
    384EI

    =
    5
    ×
    120 × 103
    ×
    (15 × 103)4
    384103200 × 103 × 42.1875 × 108

    = 93.75 mm

    Correct Option: A

    Moment of inertia

    I =
    bh3
    =
    120 × (750)3
    = 42.1875 × 108 mm4
    1212

    Maximum deflection in the beam is given by
    δ =
    5
    wL4
    384EI

    =
    5
    ×
    120 × 103
    ×
    (15 × 103)4
    384103200 × 103 × 42.1875 × 108

    = 93.75 mm


  1. The beam is subjected to a maximum bending moment of









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    Maximum bending moment occurs at the centre

    =
    wL2
    =
    20 × (15)2
    = 3375 kNm
    88

    Correct Option: A

    Maximum bending moment occurs at the centre

    =
    wL2
    =
    20 × (15)2
    = 3375 kNm
    88



  1. A concentrated load P acts on a simply supported beam of span L at a distance L/3 from the left support. The bending moment at the point of application of the load is given by









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    For horizontal equilibrium
    R1 + R2 = P
    Taking moment about R1, we have
    R2 × L = P × L/3

    R2 =
    P
    3

    ∴ R1 =
    2P
    3


    The bending moment at the point of application of load = Area under OABC
    =
    2P
    ×
    L
    =
    2PL
    339

    Correct Option: D

    For horizontal equilibrium
    R1 + R2 = P
    Taking moment about R1, we have
    R2 × L = P × L/3

    R2 =
    P
    3

    ∴ R1 =
    2P
    3


    The bending moment at the point of application of load = Area under OABC
    =
    2P
    ×
    L
    =
    2PL
    339