Strength Of Materials Miscellaneous
- A simply supported laterally loaded beam was found to deflect more than a specified value. Which of the following measures will reduce deflection?
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From differential equation of elastic curve
EI d2y = M dx2
where y = deflection of beam.
As the I = Area moment increases, the deflection will reduce.Correct Option: A
From differential equation of elastic curve
EI d2y = M dx2
where y = deflection of beam.
As the I = Area moment increases, the deflection will reduce.
- Consider a prismatic straight beam of length L = π m, pinned at the two ends as shown i n t he figure. The beam has a square cross-section of side p = 6 mm. The Young's modulus E = 20 GPa, and the coefficient of thermal expansion α = 3 × 10– 6 K – 1. The minimum temperature rise required to cause Euler buckling of the beam is ______ K.
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Length of prismatic beam,
L = πm
Pth = Paxialor αTEA = π2EI L2
⇒ 3 × 10-6 × ∆T × 6 × 6 × 10-6
∆T = 1KCorrect Option: A
Length of prismatic beam,
L = πm
Pth = Paxialor αTEA = π2EI L2
⇒ 3 × 10-6 × ∆T × 6 × 6 × 10-6
∆T = 1K
- A column has a rectangular cross-section of 10 mm × 20 mm and a length of 1 m. The slenderness ratio of the column is close to
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Slenderness ratio
= Effective length of column least radius of gyration = Le K
where Imin = minimum area moment of inertia i.e. Ixx or Iyy, whichever is less.
For given sectionImin 20 × 103 = 1667 mm3 12 and ratio= 1000 = 346 2.89 Correct Option: B
Slenderness ratio
= Effective length of column least radius of gyration = Le K
where Imin = minimum area moment of inertia i.e. Ixx or Iyy, whichever is less.
For given sectionImin 20 × 103 = 1667 mm3 12 and ratio= 1000 = 346 2.89
- The minimum axial compressive load, P required to initiate buckling for a pinned-pinned slender column with bending stiffness EI and length L is
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P = π2EI L2 Correct Option: B
P = π2EI L2
- A steel column of rectangular section (15 mm × 10 mm) and length 1.5 m is simply supported at both ends. Assuming modulus of elasticity, E = 200 GPa for steel, the critical axial load (in kN) is _____ (correct to two decimal places)
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Steel column supported at both ends = hinged at both ends.
so for hinged condition:-
Effective length, Le = L
so buckling loadCorrect Option: A
Steel column supported at both ends = hinged at both ends.
so for hinged condition:-
Effective length, Le = L
so buckling load