Strength Of Materials Miscellaneous
- The Poisson's ratio for a perfectly incompressible linear elastic material is
-
View Hint View Answer Discuss in Forum
NA
Correct Option: B
NA
- A square plate of dimension L × L is subjected to a uniform pressure load p = 250 MPa on its edges as shown in the figure. Assume plane stress conditions. The Young's modulus E= 200 GPa.
The deformed shape is a square of dimension L – 2δ. If L = 2 m and δ = 0.001 m, the Poisson's ratio of the piate material is ________.
-
View Hint View Answer Discuss in Forum
ΔV = σ (1 − v) V E
εv = εx + εy εzεv = σ − μσ + σ − μσ − μ(σ + σ) E E E E E
Due to plane stress condition εz = 0εv = σ × 2 × (1 − μ) E (2 − 2 × 0.001)2 = − P × 2(1 − μ) 22 E − 2 × 10−3 = 250 × 2 × (1 − μ) 200 × 103 250 = 1 − μ 200
0.8 = 1 − μ
∴ μ = 0.2Correct Option: A
ΔV = σ (1 − v) V E
εv = εx + εy εzεv = σ − μσ + σ − μσ − μ(σ + σ) E E E E E
Due to plane stress condition εz = 0εv = σ × 2 × (1 − μ) E (2 − 2 × 0.001)2 = − P × 2(1 − μ) 22 E − 2 × 10−3 = 250 × 2 × (1 − μ) 200 × 103 250 = 1 − μ 200
0.8 = 1 − μ
∴ μ = 0.2
- If the Poisson's ratio of an elastic material is 0.4, the ratio of modulus of rigidity to Young's modulus is ______
-
View Hint View Answer Discuss in Forum
From E = 2G(1 + μ)
G = 1 E 2(1 + μ) = l = 0.357 2(1 + 0.4) Correct Option: B
From E = 2G(1 + μ)
G = 1 E 2(1 + μ) = l = 0.357 2(1 + 0.4)
- A metallic rod of 500 mm length and 50 mm diameter, when subjected to a tensile force of 100 kN at the ends, experiences an increase in its length by 0.5 mm and a reduction in its diameter by 0.015 mm. The Poisson's ratio of the rod material is _______
-
View Hint View Answer Discuss in Forum
l = 500 mm, d = 50 mm, p = 100 KN
δl = 0.5 mm, δd = 0.015
Poission’s Ratiol = Lateral strain m longitudinal strain δd/d = 0.015/50 = 0.3. δl/l 0.5/500 Correct Option: A
l = 500 mm, d = 50 mm, p = 100 KN
δl = 0.5 mm, δd = 0.015
Poission’s Ratiol = Lateral strain m longitudinal strain δd/d = 0.015/50 = 0.3. δl/l 0.5/500
- Consider the stress-strain curve for an ideal elastic-plastic strain hardening metal as shown in the figure. The metal was loaded in uniaxial tension starting from O. Upon loading, the stress-strain curve passes through initial yield point at P, and then strain hardens to point Q, where the loading was stopped. From point Q, the specimen was unloaded to point R, where the stress is zero. I f the same specimen is reloaded in tension from point R, the value of stress τ which the material yields again is _____MPa
-
View Hint View Answer Discuss in Forum
As the point loaded beyond the yield point is unloaded completely and reloaded then because of strain hardening (residual strain remains in body) increase the yield strength.
In this case material with start yielding from point ‘R’ instead of ‘P’.Correct Option: C
As the point loaded beyond the yield point is unloaded completely and reloaded then because of strain hardening (residual strain remains in body) increase the yield strength.
In this case material with start yielding from point ‘R’ instead of ‘P’.