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A rod of length 20 mm is stretched to make a rod of length 40 mm. Subsequently, it is compressed to make a rod of final length 10 mm. Consider the longitudinal tensile strain as positive and compressive strain as negative. The total true longitudinal strain in the rod is
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- –0.5
- –0.69
- –0.75
- –1.0
- –0.5
Correct Option: B
Volume remain same L1 = 20 mm, L2 = 40 mm, L3 = 10mm
A1 L1 = A2 L2 = A3 L3
= | ||||
A3 | L1 |
True strain = ln | = ln | = -0.693 | ||||||
A3 | L1 |