Number System


  1. A rational number between 1/2 and 3/5 is :









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    Required number

    =
    1
    +
    3
    25
    2

    =
    5 + 6
    =
    11
    2020
    Required number
    =
    1
    +
    3
    25
    2

    =
    5 + 6
    =
    11
    2020

    Correct Option: C

    Required number

    =
    1
    +
    3
    25
    2

    =
    5 + 6
    =
    11
    2020


  1. The sum of the first two of three consecutive odd numbers is 33 more than the third number.
    What is the second number ?









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    x + x + 2 = x + 4 + 33
    ⇒  x + 2 = 37

    Correct Option: B

    x + x + 2 = x + 4 + 33
    ⇒  x + 2 = 37



  1. 64329 is divided by a certain number, the successive remainders being 175, 114 and 213 respectively. What are the divisor and the quotient respectively ?









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    Here, 643 – 175 = 468
    ∴  Divisor = 468 or 234

    Divisor = 234
    Quotient = 274

    Correct Option: A


    Here, 643 – 175 = 468
    ∴  Divisor = 468 or 234

    Divisor = 234
    Quotient = 274


  1. Natu and Buchku each have certain number of oranges. Natu says to Buchku, “If you give me 10 of your oranges, I will have twice the number of oranges left with you”. Buchku replies,“If you give me 10 of your oranges, I will have the same number of oranges as left with you”. What is the number of oranges with Natu and Buchku, respectively ?









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    Let the number of oranges with Natu be x.
    Number of oranges with Buchku = y
    Case I,
    x + 10 = 2 (y – 10)
    ⇒  x + 10 = 2y – 20
    ⇒  2y – x = 20 + 10 = 30   ..(i)
    Case II,
    y + 10 = x – 10
    ⇒  x – y = 10 + 10 = 20    ... (ii)
    On adding equations (i) and (ii),
    2y – x + x – y = 30 + 20
    ⇒  y = 50
    From equation (ii),
    x – 50 = 20
    ⇒  x = 50 + 20 = 70

    Correct Option: B

    Let the number of oranges with Natu be x.
    Number of oranges with Buchku = y
    Case I,
    x + 10 = 2 (y – 10)
    ⇒  x + 10 = 2y – 20
    ⇒  2y – x = 20 + 10 = 30   ..(i)
    Case II,
    y + 10 = x – 10
    ⇒  x – y = 10 + 10 = 20    ... (ii)
    On adding equations (i) and (ii),
    2y – x + x – y = 30 + 20
    ⇒  y = 50
    From equation (ii),
    x – 50 = 20
    ⇒  x = 50 + 20 = 70



  1. The value of x in the following equation is :
    0.3 + 0.6 + 0.7 + 0.8 = x









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    x = 0.3 + 0.6 + 0.7 + 0.8

    =
    3
    +
    6
    +
    7
    +
    9
    9999

    =
    3
    +
    6
    +
    7
    +
    9
    9999

    Correct Option: C

    x = 0.3 + 0.6 + 0.7 + 0.8

    =
    3
    +
    6
    +
    7
    +
    9
    9999

    =
    3
    +
    6
    +
    7
    +
    9
    9999