Number System
- A number when divided by 91 gives a remainder 17. When the same number is divided by 13, the remainder will be :
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Here, the first divisor (91) is a multiple of second divisor (13).
Correct Option: B
Here, the first divisor (91) is a multiple of second divisor (13).
∴ Required remainder = Remainder obtained on dividing 17 by 13
⇒ 17 = ( 13 × 1 ) + 4
Hence Required remainder = 4
- When an integer K is divided by 3, the remainder is 1, and when K + 1 is divided by 5, the remainder is 0. Of the following, a possible value of K is
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Of the given alternatives,
When 64 is divided by 3, remainder = 1Correct Option: C
Of the given alternatives,
When 64 is divided by 3, remainder = 1
When 65 is divided by 5, remainder = 0
- 47 is added to the product of 71 and an unknown number. The new number is divisible by 7 giving the quotient 98. The unknown number is a multiple of
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Let the unknown number be p.
∴ 71 × p + 47 = 98 × 7
⇒ 71p = 686 – 47 = 639Correct Option: D
Let the unknown number be p.
∴ 71 × p + 47 = 98 × 7
⇒ 71p = 686 – 47 = 639
⇒ p =639 = 9 = 3 × 3 71
Thus , The unknown number is a multiple of 3 .
- (461 + 462 + 463) is divisible by
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The Expression 461 + 462 + 463 = 461 (1 + 4 + 42)
Correct Option: A
The Expression 461 + 462 + 463 = 461 (1 + 4 + 42)
= 461 × 21 which is divisible by 3.
Hence , the given expression is divisible by 3 .
- The expression 26n – 42n, where n is a natural number is always divisible by
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The given expression 26n − 42n = (26)n − (42)n
Correct Option: D
The expression 26n − 42n = (26)n − (42)n
= 64n − 16n
which is divisible by 64 –16= 48
Therefore required answer is 48 .