Number System


  1. A number when divided by 91 gives a remainder 17. When the same number is divided by 13, the remainder will be :









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    Here, the first divisor (91) is a multiple of second divisor (13).

    Correct Option: B

    Here, the first divisor (91) is a multiple of second divisor (13).
    ∴ Required remainder = Remainder obtained on dividing 17 by 13
    ⇒ 17 = ( 13 × 1 ) + 4
    Hence Required remainder = 4


  1. When an integer K is divided by 3, the remainder is 1, and when K + 1 is divided by 5, the remainder is 0. Of the following, a possible value of K is









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    Of the given alternatives,
    When 64 is divided by 3, remainder = 1

    Correct Option: C

    Of the given alternatives,
    When 64 is divided by 3, remainder = 1
    When 65 is divided by 5, remainder = 0



  1. 47 is added to the product of 71 and an unknown number. The new number is divisible by 7 giving the quotient 98. The unknown number is a multiple of









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    Let the unknown number be p.
    ∴  71 × p + 47 = 98 × 7
    ⇒   71p = 686 – 47 = 639

    Correct Option: D

    Let the unknown number be p.
    ∴  71 × p + 47 = 98 × 7
    ⇒   71p = 686 – 47 = 639


    ⇒  p =
    639
    = 9 = 3 × 3
    71

    Thus , The unknown number is a multiple of 3 .


  1. (461 + 462 + 463) is divisible by









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    The Expression 461 + 462 + 463 = 461 (1 + 4 + 42)

    Correct Option: A

    The Expression 461 + 462 + 463 = 461 (1 + 4 + 42)
    = 461 × 21 which is divisible by 3.
    Hence , the given expression is divisible by 3 .



  1. The expression 26n – 42n, where n is a natural number is always divisible by









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    The given expression 26n − 42n = (26)n − (42)n

    Correct Option: D

    The expression 26n − 42n = (26)n − (42)n
    = 64n − 16n
    which is divisible by 64 –16= 48
    Therefore required answer is 48 .