Number System


  1. (271 + 272 + 273 + 274) is divisible by









  1. View Hint View Answer Discuss in Forum

    Expression = (271 + 272 + 273 + 274)
    Expression = 271 (1 +2 + 4 + 8)

    Correct Option: B

    Expression = (271 + 272 + 273 + 274)
    Expression = 271 (1 +2 + 4 + 8)
    = 271 × 15 = 271 × 3 × 5 , Which is exactly divisible by 10.
    Therefore required answer is 10 .


  1. By which number should 0.022 be multiplied so that product becomes 66 ?









  1. View Hint View Answer Discuss in Forum

    Let required number be p.
    According to question ,
    ∴  0.022 × p = 66

    Correct Option: A

    Let required number be p.
    According to question ,
    ∴  0.022 × p = 66

    ⇒  p =
    66
    = 3000
    0.22



  1. (325 + 326 + 327 + 328) is divisible by









  1. View Hint View Answer Discuss in Forum

    Expression = 325 + 326 + 327 + 328
    = 325 (1 + 3 + 32 + 33)

    Correct Option: D

    Expression = 325 + 326 + 327 + 328
    = 325 (1 + 3 + 32 + 33)
    = 325 (1 + 3 + 9 + 27)
    = 325 × 40, which is clearly divisible by 30.
    Hence the given expression is divisible by 30.


  1. Both the end digits of a 99 digit number N are 2. N is divisible by 11, then all the middle digits are :









  1. View Hint View Answer Discuss in Forum

    A number is divisible by 11 if the difference of the sum of digits at odd and even places be either zero or multiple of 11.

    Correct Option: D

    A number is divisible by 11 if the difference of the sum of digits at odd and even places be either zero or multiple of 11. If the middle digit be 4, then 24442 or 244442 etc are divisible by 11.



  1. A 4-digit number is formed by repeating a 2-digit number such as 2525, 3232, etc. Any number of this form is always exactly divisible by :









  1. View Hint View Answer Discuss in Forum

    Let the unit digit be p and ten’s digit be q.
    ∴ Number = 1000q + 100p + 10q + p
    Number = 1010q + 101p = 101(10q + p)

    Correct Option: D

    Let the unit digit be p and ten’s digit be q.
    ∴ Number = 1000q + 100p + 10q + p
    Number = 1010q + 101p = 101(10q + p)
    Clearly, this number is divisible by 101, which is the smallest three-digit prime number.