Number System
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999 998 × 999 is equal to : 999
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999 998 × 999 999 = 999 998 × 999 999
Correct Option: A
999 998 × 999 999 = 999 998 × 999 999
Required answer = 9992 + 998
Required answer = (1000 – 1)2 + 998
Required answer = 1000000 – 2000 + 1 + 998
Required answer = 998999
- The number which is to be added to 0.01 to get 1.1, is
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Let p be added to given number .
According to question ,
⇒ p + 0.01 = 1.1
⇒ p = 1.1 - 0.01Correct Option: B
Let p be added to given number .
According to question ,
⇒ p + 0.01 = 1.1
⇒ p = 1.1 - 0.01
∴ Required number = 1.1 – 0.01 = 1.09
- If [n] denotes the greatest integer < n and (n) denotes the smallest integer > n, where n is any real number, then
1 1 × 1 1 − 1 1 ÷ 1 1 + (1.5) is 5 5 5 5
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[n] < n (integer); (n) > n (integer)
∴ Expression1 1 × 1 1 − 1 1 ÷ 1 1 + (1.5) = 2 × 1 – 2 ÷ 1 + 2 5 5 5 5 Correct Option: B
[n] < n (integer); (n) > n (integer)
∴ Expression1 1 × 1 1 − 1 1 ÷ 1 1 + (1.5) = 2 × 1 – 2 ÷ 1 + 2 = 2 5 5 5 5
- Which one of the following will completely divide 571 + 572 + 573 ?
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571 + 572 + 573 = 571 (1 + 5 + 52)
Correct Option: C
571 + 572 + 573 = 571 (1 + 5 + 52)
⇒ 571 + 572 + ⇒ 573 = 571 × which is exactly divisible by 155.
Hence required answer is 155 .
- The smallest number that must be added to 803642 in order to obtain a multiple of 11 is
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∴ The required number = 11 – 4 = 7
2nd Method to solve this question :
Sum of digits at odd places = 2 + 6 + 0 = 8Correct Option: C
∴ The required number = 11 – 4 = 7
2nd Method to solve this question :
Sum of digits at odd places = 2 + 6 + 0 = 8, sum of digits at even places = 4 + 3 + 8 = 15. For divisibility by 11, difference i.e., (15 – 8) = 0 or mutiple of 11.
∴ The required number = 7