Number System


  1. Find the largest number, which exactly divides every number of the form (n3 – n) (n –2) where n isa natural number greater than 2.









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    (n3 – n) (n – 2)
    = n (n – 1) (n + 1) (n – 2)

    Correct Option: C

    (n3 – n) (n – 2)
    = n (n – 1) (n + 1) (n – 2)
    When n = 3,
    Number = 3 × 2 × 4 = 24


  1. How many numbers between 1000 and 5000 are exactly divisible by 225 ?









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    When we divide 1000 by 225,
    quotient = 4
    When we divide 5000 by 225,
    quotient = 22

    Correct Option: B

    When we divide 1000 by 225,
    quotient = 4
    When we divide 5000 by 225,
    quotient = 22
    ∴  Required answer = 22 – 4 = 18



  1. The greatest whole number, by which the expression n4 + 6n3 +11n2 + 6n + 24 is divisible for every natural number n, is









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    For n = 1
    n4 + 6n3 +11n2 + 6n + 24
    ⇒ n4 + 6n3 +11n2 + 6n + 24 = 1 + 6 + 11 + 6 + 24 = 48
    For n = 2
    n4 + 6n3 +11n2 + 6n + 24

    Correct Option: D

    For n = 1
    n4 + 6n3 +11n2 + 6n + 24
    ⇒ n4 + 6n3 +11n2 + 6n + 24 = 1 + 6 + 11 + 6 + 24 = 48
    For n = 2
    n4 + 6n3 +11n2 + 6n + 24 = 16 + 48 + 44 + 12 + 24
    ⇒ n4 + 6n3 +11n2 + 6n + 24 = 144 , which is divisible by 48.
    Clearly, 48 is the required number.


  1. It is given that (232 + 1) is exactly divisible by a certain number. which one of the following is also definitely divisible by the same number ?









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    296 + 1 = (232)3 + 13
    296 + 1 = (232 + 1) (264 – 232 + 1)

    Correct Option: A

    296 + 1 = (232)3 + 13
    296 + 1 = (232 + 1) (264 – 232 + 1)
    Clearly, 232 + 1 is a factor of 296 + 1
    Hence required answer is 296 + 1 .



  1. What least number, of 5 digits is divisible by 41?









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    As we know that , The least number of 5 digits = 10000

    Correct Option: B

    As we know that , The least number of 5 digits = 10000

    ∴  Required number = 10000 + (41 – 37)
    Hence Required number = 10004