Number System


  1. Find the greatest number of 4 digits and the least number of 5 digits which when divided by 789 leave a remainder 5 in each case.









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    The greatest number of 4 digits = 9999
    Now, we divide 9999 by 789

    Thus, when 9999 – 531= 9468 is divided by 789, no remainder is left.
    The required greatest number of
    4 digits = 9468 + 5 = 9473
    The least number of 5 digits
    = 10000

    Remainder = 532
    ∴  The least number of 5 digits exactly divisible by 789
    = 10000 + (789 – 532)
    = 10000 + 257 = 10257
    ∴  The required number
    = 10257 + 5 = 10262
    Remark : If 532 is subtracted from 10000 the number obtained 9468 is exactly divisible by 789 but in that case, the number will not be of 5 digits but of 4 digits.

    Correct Option: A

    The greatest number of 4 digits = 9999
    Now, we divide 9999 by 789

    Thus, when 9999 – 531= 9468 is divided by 789, no remainder is left.
    The required greatest number of
    4 digits = 9468 + 5 = 9473
    The least number of 5 digits
    = 10000

    Remainder = 532
    ∴  The least number of 5 digits exactly divisible by 789
    = 10000 + (789 – 532)
    = 10000 + 257 = 10257
    ∴  The required number
    = 10257 + 5 = 10262
    Remark : If 532 is subtracted from 10000 the number obtained 9468 is exactly divisible by 789 but in that case, the number will not be of 5 digits but of 4 digits.


  1. Find the number nearest to 12199 which is exactly divisible by the product of the first four
    prime numbers.









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    As we know, the first four prime numbers are 2, 3, 5, 7
    Their product = 2 × 3 × 5 × 7 = 210
    Now, we divide 12199 by 210

    Here, D – R = 210 – 19 = 191
    So, (D – R) > R.
    Hence, the required number
    = 12199 – R = 12199 – 19
    = 12180

    Correct Option: D

    As we know, the first four prime numbers are 2, 3, 5, 7
    Their product = 2 × 3 × 5 × 7 = 210
    Now, we divide 12199 by 210

    Here, D – R = 210 – 19 = 191
    So, (D – R) > R.
    Hence, the required number
    = 12199 – R = 12199 – 19
    = 12180



  1. Find the number nearest to 77685 which is exactly divisible by 720.









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    We divide 77685 by 720

    Here, D – R = 720 – 645 = 75 < R.
    ∴  The required number
    = 77685 + 75 = 77760

    Correct Option: C

    We divide 77685 by 720

    Here, D – R = 720 – 645 = 75 < R.
    ∴  The required number
    = 77685 + 75 = 77760


  1. Find the nearest number to 56586 which is exactly divisible by 552.









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    We divide 56586 by 552

    ∴  R = 282
    D = 552
    ∴  D – R = 552 – 282 = 270
    Here, (D – R) < R
    So, we get the required number
    by adding (D – R) to the dividend.
    Therefore, the number nearest to 56586 that is exactly divisible by 552 is
    56586 + 270 = 56856

    Correct Option: B

    We divide 56586 by 552

    ∴  R = 282
    D = 552
    ∴  D – R = 552 – 282 = 270
    Here, (D – R) < R
    So, we get the required number
    by adding (D – R) to the dividend.
    Therefore, the number nearest to 56586 that is exactly divisible by 552 is
    56586 + 270 = 56856



  1. Find the least number of five digits which is divisible by 666.









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    The least number of five digits = 10000
    Now, we divide 10000 by 666

    Here, we have 10 as remainder.
    Therefore, the least number to be added to the least number of 5 digits, i.e., 10000 to get the least number of 5 digits which is exactly divisible by 666 is 666– 10 or 656.
    Hence, the required number
    = 10000 + 656 = 10656.

    Correct Option: A

    The least number of five digits = 10000
    Now, we divide 10000 by 666

    Here, we have 10 as remainder.
    Therefore, the least number to be added to the least number of 5 digits, i.e., 10000 to get the least number of 5 digits which is exactly divisible by 666 is 666– 10 or 656.
    Hence, the required number
    = 10000 + 656 = 10656.