Number System


  1. In a school 1/10 of the boys are same in number as 1/4 of the girls and 5/8 of the girls are same in number as 1/4 of the boys. The ratio of the boys to girls in that school is









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    Required Number
    = 100x + 10y + z
    ∵  10y + z = 6m
    ∴  Number = 100x + 6m, where m is a positive integer.
    = 2 (50x + 3m)

    Correct Option: C

    Required Number
    = 100x + 10y + z
    ∵  10y + z = 6m
    ∴  Number = 100x + 6m, where m is a positive integer.
    = 2 (50x + 3m)


  1. A, B, C and D purchase a gift worth ₹ 60. A pays 1/2 of what others are paying, B pays
    1/3 of what others are paying and C pays 1/4 of what others are paying. What is the amount paid by D ?









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    (x – 2) is a factor of polynomial P (x) = x3 + x2 – 5x + λ.
    ∴  P(2) = 0 (i.e., on putting x = 2)
    ⇒  23 + 22 – 5 × 2 + λ = 0
    ⇒  8 + 4 – 10 + λ = 0
    ⇒  λ + 2 = 0
    ⇒  λ = –2

    Correct Option: B

    (x – 2) is a factor of polynomial P (x) = x3 + x2 – 5x + λ.
    ∴  P(2) = 0 (i.e., on putting x = 2)
    ⇒  23 + 22 – 5 × 2 + λ = 0
    ⇒  8 + 4 – 10 + λ = 0
    ⇒  λ + 2 = 0
    ⇒  λ = –2



  1. In an office, there are 108 tables and 132 chairs. If 1/6 of the tables and 1/4 of the chairs are broken. How many people can work in the office if each person requires one
    table and one chair?









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    We have to find such numbers which are divisible by 12 (LCM of 4 and 6).
    Number of numbers divisible by 12 and lying between 1 to 600

    =
    600
    − 1 = 49
    12

    Number of numbers divisible by
    12 from 1 to 100 =
    100
    = 8
    12

    ∴ Required answer
    = 49 – 8 = 41

    Correct Option: C

    We have to find such numbers which are divisible by 12 (LCM of 4 and 6).
    Number of numbers divisible by 12 and lying between 1 to 600

    =
    600
    − 1 = 49
    12

    Number of numbers divisible by
    12 from 1 to 100 =
    100
    = 8
    12

    ∴ Required answer
    = 49 – 8 = 41


  1. A person gives 1/4 of his property to his daughter, 1/2 to his sons and 1/5 for charity. How much has he given away ?









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    Here, first divisor (175) is a multiple of second divisor (25).
    ∴  Required remainder = Remainder obtained on dividing 132 by 25 = 7

    Correct Option: B

    Here, first divisor (175) is a multiple of second divisor (25).
    ∴  Required remainder = Remainder obtained on dividing 132 by 25 = 7



  1. A number whose one-fifth part increased by 4 is equal to its one-fourth part diminished by 10, is :









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    Here, 280 is a multiple of 35.
    ∴  Required remainder
    = Remainder obtained on dividing 115 by 35 = 10

    Correct Option: B

    Here, 280 is a multiple of 35.
    ∴  Required remainder
    = Remainder obtained on dividing 115 by 35 = 10