256. If V_i = 2 V, then output V₀ is:

1. 1. – 3 V

   
   
   

   2. – 6 V

   
   
   

   3. 6 V

   
   
   

   4. 3 V

   
   
   

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1. View Hint View Answer Discuss in Forum

   V_i = 2V
   V_i > 0, then V₀ < 0, diode D₂ conduct while D₁ not conduct
   

   V0 = – Vi		Rf
   		R1

   
   

   or V0 = – 2.	6	= – 6 V
   	2

   
   

   Correct Option: B

   V_i = 2V
   V_i > 0, then V₀ < 0, diode D₂ conduct while D₁ not conduct
   

   V0 = – Vi		Rf
   		R1

   
   

   or V0 = – 2.	6	= – 6 V
   	2

   
   

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257. Calculate value of i₀
     
     
     

1. 1. – 18 A

   
   
   

   2. – 24 A

   
   
   

   3. 24 A

   
   
   

   4. 36 A

   
   
   

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1. View Hint View Answer Discuss in Forum

   KCL at inverting node
   6 = 0 – V_o 6
   or V₀ = – 36
   KCL at output node
   

   	V0	+	V0 – 0	= io
   	2		6

   
   

   or io =	4V0	= 4 ×	– 36	= – 24 A
   	6		6

   
   

   Correct Option: B

   KCL at inverting node
   6 = 0 – V_o 6
   or V₀ = – 36
   KCL at output node
   

   	V0	+	V0 – 0	= io
   	2		6

   
   

   or io =	4V0	= 4 ×	– 36	= – 24 A
   	6		6

   
   

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258. The ideal characteristics of op-amp are:
     (i) input impedance, R_i = ∞
     (ii) output impedance, R₀ = ∞
     (iii) bandwidth impedance, BW = 0
     (iv) gain impedance, A = ∞ The correct statement are:

1. 1. (i) and (ii)

   
   
   

   2. (i), (ii) and (iii)

   
   
   

   3. (i) and (iv)

   
   
   

   4. All of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   NA

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259. In the circuit shown below the input offset voltage and input offset current are V_io = 4 mV and I_io = 150 nA. The total output offset voltage is:
     
     
     

1. 1. 479 mV

   
   
   

   2. 234 mV

   
   
   

   3. 168 mV

   
   
   

   4. 116 mV

   
   
   

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1. View Hint View Answer Discuss in Forum

   Total output offset voltage is given by relation
   

   VOT =		1 +	Rf		Vos + Rf. IB
   			R1

   
   where, V_OT = total output offset voltage
   R_f = feedback resistance
   V_os = input offset voltage
   I_B = input offset current Now,
   

   VOT =		1 +	500		4 × 10–3 + 5000 × 103 × 150 × 10–9
   			5

   
   V_OT = 404 × 10^–3 + 75 × 10^–3
   or V_OT = 479 × 10^–3 = 479 mV.

   
   

   Correct Option: A

   Total output offset voltage is given by relation
   

   VOT =		1 +	Rf		Vos + Rf. IB
   			R1

   
   where, V_OT = total output offset voltage
   R_f = feedback resistance
   V_os = input offset voltage
   I_B = input offset current Now,
   

   VOT =		1 +	500		4 × 10–3 + 5000 × 103 × 150 × 10–9
   			5

   
   V_OT = 404 × 10^–3 + 75 × 10^–3
   or V_OT = 479 × 10^–3 = 479 mV.

   
   

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260. In the circuit of fig. shown the op-amp slew rate is SR = 0.5 V/µs. If the amplitude of input signal is 0.02 V, then the maximum frequency that may be used is:
     
     
     

1. 1. 0.55 × 10⁶ rad/s

   
   
   

   2. 0.55 rad/s

   
   
   

   3. 1.1 × 10⁶ rad/s

   
   
   

   4. 1.1 rad/s

   
   
   

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1. View Hint View Answer Discuss in Forum

   Max. output voltage
   

   Vo = Vi		–	240		= 24 × 0.02
   			10

   
   = 0.48 V
   S.R. 2 π f_max. V_max
   or S.R.. V_o
   

   or	S.R.
   	Vo

   
   

   or =	0·5 × 106	= 1.1 × 106 rad/s.
   	0·48

   Correct Option: C

   Max. output voltage
   

   Vo = Vi		–	240		= 24 × 0.02
   			10

   
   = 0.48 V
   S.R. 2 π f_max. V_max
   or S.R.. V_o
   

   or	S.R.
   	Vo

   
   

   or =	0·5 × 106	= 1.1 × 106 rad/s.
   	0·48

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