Ratio, Proportion
- A fruit seller sold big, medium and small sized apples for ₹ 15, ₹ 10 and ₹ 5 respectively. The total number of apples sold were in the ratio 3 : 2 : 5. Find the average cost of an apple.
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Ratio of values
= 15 × 3 : 10 × 2 : 5 × 5
= 45 : 20 : 25∴ Required average cost = 45 + 20 + 25 10 = 90 = ₹ 9 10 Correct Option: C
Ratio of values
= 15 × 3 : 10 × 2 : 5 × 5
= 45 : 20 : 25∴ Required average cost = 45 + 20 + 25 10 = 90 = ₹ 9 10
- In a school, the ratio of boys to girls is 4 : 3 and the ratio of girls to teachers is 8 : 1. The ratio of students to teachers is :
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Boys : Girls
= 4 : 3 = 32 : 24
Girls : Teachers
= 8 : 1 = 24 : 3
∴ Boys : Girls : Teachers
= 32 : 24 : 3
∴ Required ratio
= (32 + 24) : 3 = 56 : 3Correct Option: A
Boys : Girls
= 4 : 3 = 32 : 24
Girls : Teachers
= 8 : 1 = 24 : 3
∴ Boys : Girls : Teachers
= 32 : 24 : 3
∴ Required ratio
= (32 + 24) : 3 = 56 : 3
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If 3x + 5 = 2 , then the value of x is 5x − 2 3
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3x + 5 = 2 5x − 2 3
⇒ 10x – 4 = 9x + 15
⇒ 10x – 9x = 15 + 4 = 19
⇒ x = 19Correct Option: B
3x + 5 = 2 5x − 2 3
⇒ 10x – 4 = 9x + 15
⇒ 10x – 9x = 15 + 4 = 19
⇒ x = 19
- A, B and C are batsmen. The ratio of the runs scored by them in a certain match are given below : A : B = 5 : 3 and B : C = 4 : 5. In all they scored 564 runs. The number of runs scored by B is:
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A : B = 5 : 3
B : C = 4 : 5
∴ A : B : C
= 5 × 4 : 3 × 4 : 3 × 5
= 20 : 12 : 15
Sum of ratios
= 20 + 12 + 15 = 47
∴ Runs scored by B= 12 × 564 = 144 47 Correct Option: D
A : B = 5 : 3
B : C = 4 : 5
∴ A : B : C
= 5 × 4 : 3 × 4 : 3 × 5
= 20 : 12 : 15
Sum of ratios
= 20 + 12 + 15 = 47
∴ Runs scored by B= 12 × 564 = 144 47
- If (a + b) : (b + c) : (c + a) = 6 : 7 : 8 and (a + b + c) = 14, then the value of c is
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a + b = b + c = c + a = k 6 7 8
⇒ a + b = 6k; b + c = 7k;
c + a = 8k
∴ a + b + b + c + c + a
= 6k + 7k + 8k
⇒ 2 (a + b + c) = 21k⇒ 2 × 14 = 21k ⇒ k = 4 3
∴ c = (a + b + c) – (a + b)= 14 − 6 × 4 = 14 − 8 = 6 3 Correct Option: A
a + b = b + c = c + a = k 6 7 8
⇒ a + b = 6k; b + c = 7k;
c + a = 8k
∴ a + b + b + c + c + a
= 6k + 7k + 8k
⇒ 2 (a + b + c) = 21k⇒ 2 × 14 = 21k ⇒ k = 4 3
∴ c = (a + b + c) – (a + b)= 14 − 6 × 4 = 14 − 8 = 6 3