Ratio, Proportion


  1. A fruit seller sold big, medium and small sized apples for ₹ 15, ₹ 10 and ₹ 5 respectively. The total number of apples sold were in the ratio 3 : 2 : 5. Find the average cost of an apple.









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    Ratio of values
    = 15 × 3 : 10 × 2 : 5 × 5
    = 45 : 20 : 25

    ∴   Required average cost =
    45 + 20 + 25
    10

    =
    90
    = ₹ 9
    10

    Correct Option: C

    Ratio of values
    = 15 × 3 : 10 × 2 : 5 × 5
    = 45 : 20 : 25

    ∴   Required average cost =
    45 + 20 + 25
    10

    =
    90
    = ₹ 9
    10


  1. In a school, the ratio of boys to girls is 4 : 3 and the ratio of girls to teachers is 8 : 1. The ratio of students to teachers is :









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    Boys : Girls
    = 4 : 3 = 32 : 24
    Girls : Teachers
    = 8 : 1 = 24 : 3
    ∴  Boys : Girls : Teachers
    = 32 : 24 : 3
    ∴  Required ratio
    = (32 + 24) : 3 = 56 : 3

    Correct Option: A

    Boys : Girls
    = 4 : 3 = 32 : 24
    Girls : Teachers
    = 8 : 1 = 24 : 3
    ∴  Boys : Girls : Teachers
    = 32 : 24 : 3
    ∴  Required ratio
    = (32 + 24) : 3 = 56 : 3



  1. If
    3x + 5
    =
    2
    , then the value of x is
    5x − 23









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    3x + 5
    =
    2
    5x − 23

    ⇒  10x – 4 = 9x + 15
    ⇒  10x – 9x = 15 + 4 = 19
    ⇒  x = 19

    Correct Option: B

    3x + 5
    =
    2
    5x − 23

    ⇒  10x – 4 = 9x + 15
    ⇒  10x – 9x = 15 + 4 = 19
    ⇒  x = 19


  1. A, B and C are batsmen. The ratio of the runs scored by them in a certain match are given below : A : B = 5 : 3 and B : C = 4 : 5. In all they scored 564 runs. The number of runs scored by B is:









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    A : B = 5 : 3
    B : C = 4 : 5
    ∴  A : B : C
    = 5 × 4 : 3 × 4 : 3 × 5
    = 20 : 12 : 15
    Sum of ratios
    = 20 + 12 + 15 = 47
    ∴  Runs scored by B

    =
    12
    × 564 = 144
    47

    Correct Option: D

    A : B = 5 : 3
    B : C = 4 : 5
    ∴  A : B : C
    = 5 × 4 : 3 × 4 : 3 × 5
    = 20 : 12 : 15
    Sum of ratios
    = 20 + 12 + 15 = 47
    ∴  Runs scored by B

    =
    12
    × 564 = 144
    47



  1. If (a + b) : (b + c) : (c + a) = 6 : 7 : 8 and (a + b + c) = 14, then the value of c is









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    a + b
    =
    b + c
    =
    c + a
    = k
    678

    ⇒  a + b = 6k; b + c = 7k;
    c + a = 8k
    ∴  a + b + b + c + c + a
    = 6k + 7k + 8k
    ⇒  2 (a + b + c) = 21k
    ⇒  2 × 14 = 21k ⇒ k =
    4
    3

    ∴  c = (a + b + c) – (a + b)
    = 14 − 6 ×
    4
    = 14 − 8 = 6
    3

    Correct Option: A

    a + b
    =
    b + c
    =
    c + a
    = k
    678

    ⇒  a + b = 6k; b + c = 7k;
    c + a = 8k
    ∴  a + b + b + c + c + a
    = 6k + 7k + 8k
    ⇒  2 (a + b + c) = 21k
    ⇒  2 × 14 = 21k ⇒ k =
    4
    3

    ∴  c = (a + b + c) – (a + b)
    = 14 − 6 ×
    4
    = 14 − 8 = 6
    3