Ratio, Proportion


  1. Marks of two candidates P and Q are in the ratio of 2 : 5. If the marks of P is 120, marks of Q will be









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    Marks of Q =
    5
    × 120 = 300
    2

    Correct Option: C

    Marks of Q =
    5
    × 120 = 300
    2


  1. If A : B = 4 : 9 and A : C = 2 : 3, then (A + B) : (A + C) is









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    A : B = 4 : 9
    A : C = 2 : 3 = 4 : 6

    ∴ 
    A + B
    =
    4 + 9
    =
    13
    A + C4 + 610

    Correct Option: C

    A : B = 4 : 9
    A : C = 2 : 3 = 4 : 6

    ∴ 
    A + B
    =
    4 + 9
    =
    13
    A + C4 + 610



  1. The third proportional to 0.8 and 0.2 is :









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    If the third proportional be x,then
    0.8 : 0.2 : : 0.2 : x
    ⇒  0.8 × x = 0.2 × 0.2

    ⇒ x =
    0.2 × 0.2
    0.8

    =
    4
    = 0.05
    80

    Second Method :
    Third proportion
    =
    b2
    =
    (0.2)2
    a0.8

    =
    0.04
    = 0.05
    0.8

    Correct Option: A

    If the third proportional be x,then
    0.8 : 0.2 : : 0.2 : x
    ⇒  0.8 × x = 0.2 × 0.2

    ⇒ x =
    0.2 × 0.2
    0.8

    =
    4
    = 0.05
    80

    Second Method :
    Third proportion
    =
    b2
    =
    (0.2)2
    a0.8

    =
    0.04
    = 0.05
    0.8


  1. If a : (b+c) = 1 : 3 and c : (a+ b) = 5:7, then b : (a+c) is equal to









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    a : (b+c) = 1: 3

    ⇒ 
    b + c
    =
    3
    b + c
    + 1 =
    3
    + 1
    a1a1

    ⇒ 
    a + b + c
    =
    3 + 1
    =
    4
       ..... (i)
    a11

    Similarly,
    a + b
    =
    7
    c5

    ⇒ 
    a + b + c
    =
    12
        ..... (ii)
    c5

    On dividing (i) by (ii),
    c
    =
    4 × 5
    =
    5
    = k    ..... (iii)
    a123

    From equation (i), b = 4k
    ∴  
    b
    =
    4k
    = 1: 2
    a + c3k + 5k

    Correct Option: A

    a : (b+c) = 1: 3

    ⇒ 
    b + c
    =
    3
    b + c
    + 1 =
    3
    + 1
    a1a1

    ⇒ 
    a + b + c
    =
    3 + 1
    =
    4
       ..... (i)
    a11

    Similarly,
    a + b
    =
    7
    c5

    ⇒ 
    a + b + c
    =
    12
        ..... (ii)
    c5

    On dividing (i) by (ii),
    c
    =
    4 × 5
    =
    5
    = k    ..... (iii)
    a123

    From equation (i), b = 4k
    ∴  
    b
    =
    4k
    = 1: 2
    a + c3k + 5k



  1. If   a : b =
    2
    :
    1
    ,
    93

    b : c =
    2
    :
    5
    and
    714

    d : c =
    7
    :
    3
    then a : b : c : d is
    105









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    a : b =
    2
    :
    1
    = 2 : 3
    93

    b : c =
    2
    :
    5
    = 4 : 5
    714

    d : c =
    7
    :
    3
    = 7 : 6
    105

    ⇒  c : d = 6 : 7
    Thus,

    = 16 : 24 : 30 : 35

    Correct Option: B

    a : b =
    2
    :
    1
    = 2 : 3
    93

    b : c =
    2
    :
    5
    = 4 : 5
    714

    d : c =
    7
    :
    3
    = 7 : 6
    105

    ⇒  c : d = 6 : 7
    Thus,

    = 16 : 24 : 30 : 35