Ratio, Proportion
- Find the mean proportional between 100 and 625.
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Let the mean proportional be x.
∴ 100 : x : x : 625Then , 100 = x x 625
⇒ x2 = 100 × 625
⇒ x = √100 × 625 = 10 × 25
= 250Correct Option: C
Let the mean proportional be x.
∴ 100 : x : x : 625Then , 100 = x x 625
⇒ x2 = 100 × 625
⇒ x = √100 × 625 = 10 × 25
= 250
- Determine the fourth proportional to 9 .6 m 7 .2 m 28.8 m .
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Let the fourth proportional be x.
∴ 9.6 kg : 7.2 kg . : : 28.8 m : xm
o r, 9.6 : 7.2 : : 28.8 : xThen , 9.6 = 28.8 7.2 x
⇒ 9.6 × x = 7.2 × 28.8⇒ x = 7.2 × 28.8 = 21.6 m 9.6 Correct Option: B
Let the fourth proportional be x.
∴ 9.6 kg : 7.2 kg . : : 28.8 m : xm
o r, 9.6 : 7.2 : : 28.8 : xThen , 9.6 = 28.8 7.2 x
⇒ 9.6 × x = 7.2 × 28.8⇒ x = 7.2 × 28.8 = 21.6 m 9.6
- If x : y = 8 : 9 , then 5 x – 4 y : 3 x + 2 y is equal to :
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x ; 8 (Given) y 9 ∴ (5x + 4y / 3x) 2y) ; 5 x + 4 y 3 x ) 2 y ; 5 " 8 + 4 9 3 " 8 ) 2 9 ; 40 + 36 ; 4 ; 2 24) 18 42 21 Correct Option: C
x ; 8 (Given) y 9 ∴ (5x + 4y / 3x) 2y) ; 5 x + 4 y 3 x ) 2 y ; 5 " 8 + 4 9 3 " 8 ) 2 9 ; 40 + 36 ; 4 ; 2 24) 18 42 21
- A mixture contains alcohol and water in the ratio 4 : 3 . If 5 litres of water is added to the mixture the ratio becomes 4 : 5 . The quantity of alcohol in the given mixture is :
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4x ; 4 3x) 5 5
⇒ 20x = 12x + 20
⇒ 8x = 20 ⇒ x = 2.5
∴ Quantity of alcohol
= 4 × 2.5 = 10 litresCorrect Option: B
4x ; 4 3x) 5 5
⇒ 20x = 12x + 20
⇒ 8x = 20 ⇒ x = 2.5
∴ Quantity of alcohol
= 4 × 2.5 = 10 litres
- Twenty years ago the ratio between the ages of Sita and Meena was 1 : 4 and at present it is 1 : 2 . What is the age of Sita at present?
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20 years ago,
Sita’s age = x years
Meena’s age = 4x years∴ x) 20 ; 1 4x) 20 2
⇒ 2x + 40 = 4x + 20
⇒ 2x = 20 ⇒ x = 10
∴ Sita’s present age = 30 yearsCorrect Option: C
20 years ago,
Sita’s age = x years
Meena’s age = 4x years∴ x) 20 ; 1 4x) 20 2
⇒ 2x + 40 = 4x + 20
⇒ 2x = 20 ⇒ x = 10
∴ Sita’s present age = 30 years