Ratio, Proportion


  1. The ratio of number of boys and girls in a school of 720 students is 7 : 5. How many more girls should be admitted to make the ratio 1 : 1 ?









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    Boys : Girls = 7 : 5

    Number of boys =
    7
    × 720 = 420
    12

    Number of girls =
    5
    × 720 = 300
    12

    Let x girls be admitted.
    According to the question,
    420 = 300 + x
    ⇒  x = 420 – 300 = 120

    Correct Option: B

    Boys : Girls = 7 : 5

    Number of boys =
    7
    × 720 = 420
    12

    Number of girls =
    5
    × 720 = 300
    12

    Let x girls be admitted.
    According to the question,
    420 = 300 + x
    ⇒  x = 420 – 300 = 120


  1. 12 monkeys can eat 12 bananas in 12 minutes. In how many minutes can 4 monkeys eat 4 bananas ?









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    ⇒  4 × 12 × x = 12 × 12 × 4

    ⇒  x =
    12 × 12 × 4
    4 × 12

    = 12 minutes

    Correct Option: B


    ⇒  4 × 12 × x = 12 × 12 × 4

    ⇒  x =
    12 × 12 × 4
    4 × 12

    = 12 minutes



  1. What must be added to each term of the ratio 2 : 5 so that it may equal to 5 : 6 ?









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    Let x be added to each term.
    According to the question,

    2 + x
    =
    5
    5 + x6

    ⇒  12 + 6x = 25 + 5x
    ⇒  6x – 5x = 25 – 12
    ⇒  x = 13

    Correct Option: C

    Let x be added to each term.
    According to the question,

    2 + x
    =
    5
    5 + x6

    ⇒  12 + 6x = 25 + 5x
    ⇒  6x – 5x = 25 – 12
    ⇒  x = 13


  1. If A : B = 2 : 3 and B : C = 3 : 7, then A + B : B + C : C + A is









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    A : B = 2 : 3
    B : C = 3 : 7
    ∴  A : B : C = 2 : 3 : 7
    ∴  A = 2k, B = 3k, C = 7k
    ∴  A + B = 5k; B + C = 10k,
    C + A = 9k
    ∴  Required ratio = 5k : 10k : 9k
    = 5 : 10 : 9

    Correct Option: C

    A : B = 2 : 3
    B : C = 3 : 7
    ∴  A : B : C = 2 : 3 : 7
    ∴  A = 2k, B = 3k, C = 7k
    ∴  A + B = 5k; B + C = 10k,
    C + A = 9k
    ∴  Required ratio = 5k : 10k : 9k
    = 5 : 10 : 9



  1. If (x3 – y3) : (x2 +xy +y2) = 5 : 1
    and (x2 – y2) : (x – y) = 7 : 1, then the ratio 2x : 3y equals









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    x3 − y3
    =
    5
    x2 + xy + y21

    ⇒ 
    (x − y)(x2 + xy + y2)
    = 5
    x2 + xy + y2

    ⇒   x – y = 5       ....(i)
    Again,
    x2 − y2
    = 7
    x − y

    ⇒ 
    (x + y)(x − y)
    = 7
    x − y

    ⇒   x + y = 7       ....(ii)
    On adding equations (i) and (ii),
    2x = 12 ⇒ x = 6
    From equation (ii),
    x + y = 7 ⇒ y = 7 – 6 = 1
    ∴ 
    2x
    =
    2 × 6
    = 4 : 1
    3y3 × 1

    Correct Option: A

    x3 − y3
    =
    5
    x2 + xy + y21

    ⇒ 
    (x − y)(x2 + xy + y2)
    = 5
    x2 + xy + y2

    ⇒   x – y = 5       ....(i)
    Again,
    x2 − y2
    = 7
    x − y

    ⇒ 
    (x + y)(x − y)
    = 7
    x − y

    ⇒   x + y = 7       ....(ii)
    On adding equations (i) and (ii),
    2x = 12 ⇒ x = 6
    From equation (ii),
    x + y = 7 ⇒ y = 7 – 6 = 1
    ∴ 
    2x
    =
    2 × 6
    = 4 : 1
    3y3 × 1