Ratio, Proportion


  1. If A : B = 2 : 1 and A : C = 1 : 3, then A : B : C is









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    A : B = 2 : 1
    A : C = 1 : 3 = 2 : 6
    ∴  A : B : C = 2 : 1 : 6

    Correct Option: D

    A : B = 2 : 1
    A : C = 1 : 3 = 2 : 6
    ∴  A : B : C = 2 : 1 : 6


  1. The mean proportion of 1.21 and 0.09 is









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    1.21
    =
    x
    x0.09

    Where = x = mean Proportion
    ⇒  x2 = 121 × 0.09
    ⇒  x2 = 1.1 × 1.1 × 0.3 × 0.3
    ⇒  x = 1.1 × 0.3 = 0.33

    Correct Option: B

    1.21
    =
    x
    x0.09

    Where = x = mean Proportion
    ⇒  x2 = 121 × 0.09
    ⇒  x2 = 1.1 × 1.1 × 0.3 × 0.3
    ⇒  x = 1.1 × 0.3 = 0.33



  1. The numbers x, y and z are respectively proportional to 2, 3 and 5 and the sum of x, y and z is 80. If the number z is given by the equation z = ax – 8, then a is









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    According to the question,
    x = 2k
    y = 3k
    z = 5k
    ∵  x + y + z = 80
    ⇒  2k + 3k + 5k = 80
    ⇒  10k = 80

    ⇒  k =
    80
    = 8
    10

    ∴  x = 2 × 8 = 16
    y = 3 × 8 = 24
    z = 5 × 8 = 40
    ∴  z = ax – 8
    ⇒  40 = a × 16 – 8
    ⇒  16a = 40 + 8 = 48
    ⇒  a =
    48
    = 3
    16

    Correct Option: C

    According to the question,
    x = 2k
    y = 3k
    z = 5k
    ∵  x + y + z = 80
    ⇒  2k + 3k + 5k = 80
    ⇒  10k = 80

    ⇒  k =
    80
    = 8
    10

    ∴  x = 2 × 8 = 16
    y = 3 × 8 = 24
    z = 5 × 8 = 40
    ∴  z = ax – 8
    ⇒  40 = a × 16 – 8
    ⇒  16a = 40 + 8 = 48
    ⇒  a =
    48
    = 3
    16


  1. Rs. 2420 were divided among A, B and C so that A : B = 5 : 4 and B : C = 9 : 10 then C gets









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    A : B = 5 : 4 = 45 : 36
    B : C = 9 : 10 = 36 : 40
    ∴  A : B : C = 45 : 36 : 40
    Sum of the terms of ratio
    = 45 + 36 + 40 = 121

    ∴  C’s share = Rs.
    40
    × 2420
    121

    = Rs. 800

    Correct Option: B

    A : B = 5 : 4 = 45 : 36
    B : C = 9 : 10 = 36 : 40
    ∴  A : B : C = 45 : 36 : 40
    Sum of the terms of ratio
    = 45 + 36 + 40 = 121

    ∴  C’s share = Rs.
    40
    × 2420
    121

    = Rs. 800



  1. Among 132 examinees of a certain school, the ratio of successful to unsuccessful students is 9 : 2. Had 4 more students passed, then the ratio of successful to unsuccessful students would have been









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    Successful students

    ⇒ 
    2
    × 132 = 24
    11

    When 4 more students succeed,
    Required ratio
    = (108 + 4) : (24 – 4)
    = 112 : 20 = 28 : 5

    Correct Option: D

    Successful students

    ⇒ 
    2
    × 132 = 24
    11

    When 4 more students succeed,
    Required ratio
    = (108 + 4) : (24 – 4)
    = 112 : 20 = 28 : 5