Introduction to Data Interpretation

Introduction to Data Interpretation

Easy Questions
Moderate Questions
Difficult Questions

Data Interpretation

Introduction to Data Interpretation
Table chart
Line chart
Pie chart
Bar graph
Mixed Graph
Data Sufficiency

Direction: In each of the following questions, the following histogram shows the relationship between the marks obtained by the students and the number of students in an examination. Study the histogram and answer the questions.

  1. The ratio of the number of students who obtained 60 or more marks to that of students who obtained 60 or less marks is








  1. View Hint View Answer Discuss in Forum

    As per the given above histogram , we can see
    Total number of students who obtained 60 or more marks = 19 + 13 = 32
    Total number of students who obtained 60 or less marks = 5 + 10 + 15 = 30
    Required ratio = Total number of students who obtained 60 or more marks : Total number of students who obtained 60 or less marks

    Correct Option: D

    As per the given above histogram , we can see
    Total number of students who obtained 60 or more marks = 19 + 13 = 32
    Total number of students who obtained 60 or less marks = 5 + 10 + 15 = 30
    Required ratio = Total number of students who obtained 60 or more marks : Total number of students who obtained 60 or less marks
    ∴ Required ratio = 32 : 30 = 16 : 15

  1. The percentage of students who obtained 40 marks or less is








  1. View Hint View Answer Discuss in Forum

    On the basis of given graph in question ,
    Total number of students = 5 + 10 + 15 + 19 + 13 = 62
    Number of students who obtained 40 marks or less = 15

    Required percent =
    Number of students who obtained 40 marks or less
    		 × 100 %
    Total number of students


    Correct Option: C

    On the basis of given graph in question ,
    Total number of students = 5 + 10 + 15 + 19 + 13 = 62
    Number of students who obtained 40 marks or less = 15

    Required percent =
    Number of students who obtained 40 marks or less
    		 × 100 %
    Total number of students

    Required percent =
    15
    		 × 100 ≈ 24.2%
    62

Direction: Study the histogram of marks (in Mathematics) distribution of 50 students of class IX and answer the following questions.

  1. The percentage of students who have secured marks more than 59 is:








  1. View Hint View Answer Discuss in Forum

    According to given graph, we have
    Students who score more than 59 marks = 4 + 13 = 17
    Total number of students = 7 + 8 + 18 + 4 + 13 = 50

    ∴ Required percent =
    Students who score more than 59 marks
    		 × 100 %
    Total number of students

    Correct Option: C

    According to given graph, we have
    Students who score more than 59 marks = 4 + 13 = 17
    Total number of students = 7 + 8 + 18 + 4 + 13 = 50

    ∴ Required percent =
    Students who score more than 59 marks
    		 × 100 %
    Total number of students

    ∴ Required percent =
    17
    		 × 100 = 34%
    50

  1. The number of students who have scored between 39 and 80 is :








  1. View Hint View Answer Discuss in Forum

    From the given above histogram , we can see
    The number of students who have scored interval 40-60 = 18
    The number of students who have scored interval 60-80 = 4
    Required answer = The number of students who have scored interval 40-60 + The number of students who have scored interval 60-80

    Correct Option: A

    From the given above histogram , we can see
    The number of students who have scored interval 40-60 = 18
    The number of students who have scored interval 60-80 = 4
    Required answer = The number of students who have scored interval 40-60 + The number of students who have scored interval 60-80
    ∴ Required answer = 18 + 4 = 22

  1. The average marks of the students are








  1. View Hint View Answer Discuss in Forum

    On the basis of given graph in question , we have
    Here , f1 = 10 , x1 = 7 , f2 = 30 , x2 = 8 , f3 = 50 , x3 = 18 , f4 = 70 , x4 = 4 , f5 = 90 , x5 = 13

    Mid-value of class-interval (x) =
    Highest value + Lowest value
    2

    ∴ Average =
    Σ fx
    Σ f

    where Σf = Total number of students
    Required average marks =
    10 × 7 + 30 × 8 + 50 × 18 + 70 × 4 + 90 × 13
    50

    Correct Option: A

    On the basis of given graph in question , we have
    Here , f1 = 10 , x1 = 7 , f2 = 30 , x2 = 8 , f3 = 50 , x3 = 18 , f4 = 70 , x4 = 4 , f5 = 90 , x5 = 13

    Mid-value of class-interval (x) =
    Highest value + Lowest value
    2

    ∴ Average =
    Σ fx
    Σ f

    where Σf = Total number of students
    Required average marks =
    10 × 7 + 30 × 8 + 50 × 18 + 70 × 4 + 90 × 13
    50

    Required average marks =
    70 + 240 + 900 + 280 + 1170
    50

    Required average marks =
    2660
    		= 53.2
    50