Introduction to Data Interpretation

Introduction to Data Interpretation

Easy Questions
Moderate Questions
Difficult Questions

Data Interpretation

Introduction to Data Interpretation
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Data Sufficiency

Direction: The table shows the percentage of total population of a city in different age groups. Study the table and answer the questions.

  1. If the difference between the number of people in the age groups (46 – 55) and (16 – 25) is 0.975 million, then the total population (in millions) of the city is








  1. View Hint View Answer Discuss in Forum

    On the basis of given table in question ,
    ∵ Difference between the number of people in the age groups (46 – 55) and (16 – 25) = 0.975 million
    Percent of people in the age groups (46 – 55) = 18.25%
    And Percent of people in the age groups (16 – 25) = 15%
    ⇒ (18.25 – 15)% ≡ 0.975 million

    Correct Option: B

    On the basis of given table in question ,
    ∵ Difference between the number of people in the age groups (46 – 55) and (16 – 25) = 0.975 million
    Percent of people in the age groups (46 – 55) = 18.25%
    And Percent of people in the age groups (16 – 25) = 15%
    ⇒ (18.25 – 15)% ≡ 0.975 million

    ∴ 100 % ≡
    0.975
    		 × 100 ≡ 30 millions
    3.25

  1. If there are 22 million people below 36 years, then the number of people (in millions) in the age group (56 – 65) is








  1. View Hint View Answer Discuss in Forum

    As per the given above table , we see
    Percentage of people below 36 years = (20 + 18.25 + 16.75)% = 55%
    Percent of people in the age group (56 – 65) = 12.50%
    ∵ 55% ≡ 22 million

    Correct Option: A

    As per the given above table , we see
    Percentage of people below 36 years = (20 + 18.25 + 16.75)% = 55%
    Percent of people in the age group (56 – 65) = 12.50%
    ∵ 55% ≡ 22 million

    ∴ 12.50 % ≡
    22
    		 × 12.50 = 5 millions
    55

Direction: Study the table and answer the questions

  1. Average height (in cm) of the girls whose heights are 155cm and above is about








  1. View Hint View Answer Discuss in Forum

    On the basis of given table in question ,
    Class interval (155 – 160) = 6 girls

    Mid-value =
    155 + 160
    		= 157.5
    2

    Class interval (160 – 165) = 5 girls
    Mid-value =
    160 + 165
    		= 162.5
    2

    ∴ Required average =
    6 × 157.5 + 5 × 162.5
    11

    Correct Option: B

    On the basis of given table in question ,
    Class interval (155 – 160) = 6 girls

    Mid-value =
    155 + 160
    		= 157.5
    2

    Class interval (160 – 165) = 5 girls
    Mid-value =
    160 + 165
    		= 162.5
    2

    ∴ Required average =
    6 × 157.5 + 5 × 162.5
    11

    Required average =
    945 + 812.5
    		=
    1757.5
    		= 159.8 cm
    33

  1. The number of girls whose height is above 150 cm is








  1. View Hint View Answer Discuss in Forum

    According to given table, we have

    Height No. of girls
    135-140 04
    140-14507
    145-150 18
    150-155 11
    155-160 06
    160-165 05

    Correct Option: A

    According to given table, we have

    Height No. of girls
    135-140 04
    140-14507
    145-150 18
    150-155 11
    155-160 06
    160-165 05

    Required answer = 11 + 6 + 5 = 22

Direction: Study the following table and answer the questions.

  1. The difference in the average number of candidates qualified in Science discipline per year from 2006 to 2008 and the average number of candidates qualified in the same discipline from 2009 to 2011 was








  1. View Hint View Answer Discuss in Forum

    As per the given above table , we see

    Candidates qualified under science discipline in year 2006 ⇒
    780 × 40
    		 = 312
    100

    Candidates qualified under science discipline in year 2007 ⇒
    650 × 42
    		 = 273
    100

    Candidates qualified under science discipline in year 2008 ⇒
    500 × 45
    		 = 225
    100

    Correct Option: A

    As per the given above table , we see

    Candidates qualified under science discipline in year 2006 ⇒
    780 × 40
    		 = 312
    100

    Candidates qualified under science discipline in year 2007 ⇒
    650 × 42
    		 = 273
    100

    Candidates qualified under science discipline in year 2008 ⇒
    500 × 45
    		 = 225
    100

    Candidates qualified under science discipline in year 2009 ⇒
    45 × 620
    		 = 279
    100

    Candidates qualified under science discipline in year 2010 ⇒
    35 × 900
    		 = 315
    100

    Candidates qualified under science discipline in year 2011 ⇒
    42 × 850
    		 = 357
    100

    Required average difference = Average number of candidates qualified in Science year from 2009 to 20011 - Average number of candidates qualified in Science year from 2006 to 2008
    Required average difference =
    1
    		[(279 + 315 + 357) – (312 + 273 + 225)] =
    1
    		 (951 – 810)
    33

    =
    1
    		 × 141 = 47
    3