Engineering Mathematics Miscellaneous
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For the matrix A = 5 3 , 1 3
ONE of the normalized eigen vectors is given as
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| A - λI | = 0
⇒ (5 – λ) (3 – λ) = 3 = 0
⇒ λ2 – 8λ + 15 – 3 = 0
⇒ λ2 – 8λ + 12 = 0
⇒ λ = 2, λ = 6
Now, at λ = 2, eign vector:
Hence required vector isCorrect Option: B
| A - λI | = 0
⇒ (5 – λ) (3 – λ) = 3 = 0
⇒ λ2 – 8λ + 15 – 3 = 0
⇒ λ2 – 8λ + 12 = 0
⇒ λ = 2, λ = 6
Now, at λ = 2, eign vector:
Hence required vector is
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Laplace transform of the function f(t) is given by F(s) = L{f(t)} =
Laplace transform of the function shown below is given by
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f(t) = 2; 0 < t < 1 > 0; otherwise
∴ L[f(t)] = = 2 - 2e-s s Correct Option: C
f(t) = 2; 0 < t < 1 > 0; otherwise
∴ L[f(t)] = = 2 - 2e-s s
- The Laplace transform of ei5t where i = √-1, is
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∴ L[ei5t] = 1 s + 5i = 1 × (s + 5i) (s - 5i) (s + 5i) = s + 5i s2 + 25
Correct Option: B
∴ L[ei5t] = 1 s + 5i = 1 × (s + 5i) (s - 5i) (s + 5i) = s + 5i s2 + 25
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Laplace transform of cos(ωt) is s s2 + ω2
The laplace transform of e–2t cos(4t) is
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We know that if L{f(t)} = F(s)
Then L{eat f(t)} = F(s – a)∴ L[e-2t cos 4t ] = s + 2 (s + 2)2 + 42 = s + 2 (s + 2)2 + 16 Correct Option: D
We know that if L{f(t)} = F(s)
Then L{eat f(t)} = F(s – a)∴ L[e-2t cos 4t ] = s + 2 (s + 2)2 + 42 = s + 2 (s + 2)2 + 16
- Laplace transform of cos (ωt) is
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Laplace transform of cos (ωt) is
L[ cos (ωt) ] = S s2 + ω2 Correct Option: A
Laplace transform of cos (ωt) is
L[ cos (ωt) ] = S s2 + ω2