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Engineering Mathematics Miscellaneous
  1. The Laplace transform of ei5t where i = √-1, is
    1. s - 5i
      s2 - 25
    2. s + 5i
      s2 + 25
    3. s + 5i
      s2 - 25
    4. s - 5i
      s2 + 25
Correct Option: B

∴ L[ei5t] =
1
s + 5i

=
1
 ×
(s + 5i)
(s - 5i)(s + 5i)

=
s + 5i
s2 + 25


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