Network Elements and the Concept of Circuit
- In the circuit shown below, S was initially open. At time t = 0, S is closed. When the current through the induc-tor is 6A, the rate of change of current through the resistor is 6 A/s. The value of inductor would be—
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As we know that VL = L di & VR = i R = 6 × 1 = 6V dt
18 = VL + VR
⇒ VL = 12V12 = L di dt
⇒ L = 2H
di 6A/S 
dt
Hence alternative (B) is the correct choice
Correct Option: B
As we know that VL = L di & VR = i R = 6 × 1 = 6V dt
18 = VL + VR
⇒ VL = 12V12 = L di dt
⇒ L = 2Hdi 6A/S dt
Hence alternative (B) is the correct choice
- For the circuit given below, the power absorbed by the load RL is—
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From given figure
I = 2V = 2 Amp. 1Ω
Voltage across load resistance
VL = 2I = 2 × 2 = 4VPower absorbed = V2L = 42 = 8W RL 2 Correct Option: B
From given figure
I = 2V = 2 Amp. 1Ω
Voltage across load resistance
VL = 2I = 2 × 2 = 4VPower absorbed = V2L = 42 = 8W RL 2
- The f-cut set matrix of a graph shown in fig. with respect to chosen tree is as given below—
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NA
Correct Option: B
NA
- The f-cut set matrix of a graph shown below with respect to chosen tree is as given below:
The oriented graph of the network is—
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NA
Correct Option: A
NA
- The f-cut set matrix of a graph is given as:
The oriented graph of the network is—
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NA
Correct Option: D
NA
