Network Elements and the Concept of Circuit


Network Elements and the Concept of Circuit

  1. Consider the network graph shown in figure. Which one of the following is 'not' a tree of this graph?











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    Because tree is a graph which have all the nodes but there is no loop formed.

    Correct Option: B

    Because tree is a graph which have all the nodes but there is no loop formed.


  1. For a given network, the number of independent mesh equations (m) and the number of independent node equations (n) are related as follows— (A) (B) (C) (D)









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    NA

    Correct Option: D

    NA



  1. For the given graph the incidence matrix `A' is given by—











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    Since the incidance matrix is given by


    Correct Option: C

    Since the incidance matrix is given by



  1. A connected graph has `b' number of branches and `n' number of nodes. Its ranks is—









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    The rank of graph having node n = n – 1.

    Correct Option: D

    The rank of graph having node n = n – 1.



  1. The Norton equivalent across BB′ is given by—











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    Calculation for RN (i.e. Rth):
    The equivalent circuit is given by

    RN = (20 || 10 + 10) || 5

    =20+ 10|| 5 = 50 3 || 5
    3

    =
    250 / 3
    =
    250
    =
    50

    (50 / 3) + 56513

    Calculation for Isc
    The equivalent circuit drawn in order to calculate I sc first calculate I.
    I =
    V
    Req

    where R veq = the equivalent resistance as seen from the terminal AA′

    or R eq = 20 + 10 || 10 = 20 + 5 = 25 Ω
    I =
    10
    =
    2
    amp. (Given, V = 10 Volt)
    255

    =
    2

    =
    1
    amp.
    5

    Correct Option: B

    Calculation for RN (i.e. Rth):
    The equivalent circuit is given by

    RN = (20 || 10 + 10) || 5

    =20+ 10|| 5 = 50 3 || 5
    3

    =
    250 / 3
    =
    250
    =
    50

    (50 / 3) + 56513

    Calculation for Isc
    The equivalent circuit drawn in order to calculate I sc first calculate I.
    I =
    V
    Req

    where R veq = the equivalent resistance as seen from the terminal AA′

    or R eq = 20 + 10 || 10 = 20 + 5 = 25 Ω
    I =
    10
    =
    2
    amp. (Given, V = 10 Volt)
    255

    =
    2

    =
    1
    amp.
    5