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In the circuit shown below, S was initially open. At time t = 0, S is closed. When the current through the induc-tor is 6A, the rate of change of current through the resistor is 6 A/s. The value of inductor would be—
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- 1H
- 2H
- 3H
- 4H
Correct Option: B
As we know that VL = L | & VR = i R = 6 × 1 = 6V | |
18 = VL + VR
⇒ VL = 12V
12 = L | dt |
⇒ L = 2H
![]() | 6A/S | ![]() | dt |
Hence alternative (B) is the correct choice
