Network Elements and the Concept of Circuit


Network Elements and the Concept of Circuit

  1. In a balanced Wheatstone bridge, if the positions of detector and source are interchanged, the bridge will still remain balanced. This inference can be drawn from—









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    NA

    Correct Option: A

    NA


  1. The value of the resistance R in the circuit shown in the given figure is varied in such a manner that the power dissipated in 5 Ω resistor is maximum. Under this condition, the value of R will be—











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    Power draw through the 5 Ω (i.e. load resistance) will be maximum if and only if Rth = RL calculation for Rth for the given circuit.

    Rth =
    8 R
    8 + R

    8 R
    = 5
    8 + R

    8R = 5R + 40
    3R = 40
    R =
    40
    3

    Correct Option: B

    Power draw through the 5 Ω (i.e. load resistance) will be maximum if and only if Rth = RL calculation for Rth for the given circuit.

    Rth =
    8 R
    8 + R

    8 R
    = 5
    8 + R

    8R = 5R + 40
    3R = 40
    R =
    40
    3



  1. Calculate the Thevenin resistance for the circuit shown below between A and B—











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    Calculation of Rth:

    Rth = 10 + (2 + 2) || 4

    = 10 +
    4 × 4
    4 + 4

    = 10 + 2 = 12 Ω

    Correct Option: B

    Calculation of Rth:

    Rth = 10 + (2 + 2) || 4

    = 10 +
    4 × 4
    4 + 4

    = 10 + 2 = 12 Ω


  1. The rms voltage measured across on admittance (G + jB) is V. The reactive power for the element is—









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    NA

    Correct Option: A

    NA



  1. If L {f (t)} =
    s2 + 2
    , then the value of lim t→∞ f (t)—









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    Given, L {f (t)} =
    s2 + 2

    or f (t) = sin t.
    as t → ∞, f (t) = sin t goes through 1 to 0
    and – 1 to 0 to infinite times so the value of Lim t→∞ f(t) cannot be determined.

    Correct Option: A

    Given, L {f (t)} =
    s2 + 2

    or f (t) = sin t.
    as t → ∞, f (t) = sin t goes through 1 to 0
    and – 1 to 0 to infinite times so the value of Lim t→∞ f(t) cannot be determined.