Trigonometry


  1. (1 + tan²A) cotA
    is equal to
    cosec²A









  1. View Hint View Answer Discuss in Forum

    Expression =
    (1 + tan²A) cotA
    cosec²A

    = sec²A . cotA . sin²A (sinA . cosecA = 1)
    =
    1
    .
    cosA
    .sin²A
    cos²AsinA

    =
    sinA
    = tanA
    cosA

    Correct Option: B

    Expression =
    (1 + tan²A) cotA
    cosec²A

    = sec²A . cotA . sin²A (sinA . cosecA = 1)
    =
    1
    .
    cosA
    .sin²A
    cos²AsinA

    =
    sinA
    = tanA
    cosA


  1. What is the value of sec 330°?









  1. View Hint View Answer Discuss in Forum

    sec 330° = sec (360° – 30°) = sec 30° = 2/3
    [∵ sec (360° – θ) = secθ]

    Correct Option: D

    sec 330° = sec (360° – 30°) = sec 30° = 2/3
    [∵ sec (360° – θ) = secθ]



  1. If
    1
    = x, then the value of x is
    (tanA + cotA)









  1. View Hint View Answer Discuss in Forum

    1
    = x
    tanA + cotB

    1
    = x
    sinA
    +
    cosA
    cosAsinA

    1
    = x
    sin²A + cos²A
    sinAcosA

    1
    = sinA.cosA
    1
    sinAcosA

    Correct Option: A

    1
    = x
    tanA + cotB

    1
    = x
    sinA
    +
    cosA
    cosAsinA

    1
    = x
    sin²A + cos²A
    sinAcosA

    1
    = sinA.cosA
    1
    sinAcosA


  1. What is the value of sin
    11π
    ?
    6









  1. View Hint View Answer Discuss in Forum

    sin
    11π
    6

    = sin 2π -
    π
    6

    [∵ sin (360° – θ)
    = sin (2π – θ) = –sin θ]
    = - sin
    π
    = -
    1
    62

    Correct Option: C

    sin
    11π
    6

    = sin 2π -
    π
    6

    [∵ sin (360° – θ)
    = sin (2π – θ) = –sin θ]
    = - sin
    π
    = -
    1
    62



  1. If secA + tanA = a, then the value of cosA is









  1. View Hint View Answer Discuss in Forum

    secA + tanA = a ..... (i)
    ∵ sec²A – tan²A = 1
    ⇒ (secA + tanA) (secA – tanA) = 1
    ² secA – tanA = 1/a ... (ii)
    On adding equations (i) and (ii),

    2 secA = a +
    1
    =
    a² + 1
    aa

    ⇒ secA =
    a² + 1
    2a

    ⇒ cosA =
    2a
    a² + 1

    Correct Option: B

    secA + tanA = a ..... (i)
    ∵ sec²A – tan²A = 1
    ⇒ (secA + tanA) (secA – tanA) = 1
    ² secA – tanA = 1/a ... (ii)
    On adding equations (i) and (ii),

    2 secA = a +
    1
    =
    a² + 1
    aa

    ⇒ secA =
    a² + 1
    2a

    ⇒ cosA =
    2a
    a² + 1