Electromagnetic theory miscellaneous
- Which of the following equation represents the Gauss law in a homogeneous isotropic medium?
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NA
Correct Option: A
NA
- For incidence from dielectric medium (∈1) into dielectric medium 2 (∈2), the Brewster angle θp and the corresponding angle of transmission θt for ∈2/ ∈1 = 3 will be respecitively—
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Brewster angle
tanθ1 = √∈2/∈1
= √3
Therefore, θ1 = 60º
and sin θ1 = √∈2
sin θ2 = ε1sin 60° = √3 sin θ2
solving, we getθ2 = 30ºCorrect Option: C
Brewster angle
tanθ1 = √∈2/∈1
= √3
Therefore, θ1 = 60º
and sin θ1 = √∈2
sin θ2 = ε1sin 60° = √3 sin θ2
solving, we getθ2 = 30º
- A transmission line of characteristic impedance Z0 = 50 ohms, phase velocity vP = 2 × 108 m/s, and length I = 1 m is terminated by a load ZL = (30 – j 40) ohms. The input impedance of the line for a frequency of 100 MHz will be—
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VP = f λ
Therefore λ = VP/ f
= 2 × 108/ 100 × 106
= 2 m
Since length of the line is half wave length i.e.I = λ = 2 = 1 2 2
Therefore, Zin = ZL
or Zin = (30 – j40) ohms.Correct Option: B
VP = f λ
Therefore λ = VP/ f
= 2 × 108/ 100 × 106
= 2 m
Since length of the line is half wave length i.e.I = λ = 2 = 1 2 2
Therefore, Zin = ZL
or Zin = (30 – j40) ohms.
- The directivity of an isotropic antenna is—
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Directivity is the ability of an antenna to radiate power in a particular direction only. The directional pattern is a polar plot gives us the strength of radiated electromagnetic wave (in case of transmitting antenna) and strength of received electromagnetic wave (in case of receiving antenna) as a function of distance and angle. The directional pattern is affected by the shape and size of antenna, point of feed of RF signal etc.
Correct Option: C
Directivity is the ability of an antenna to radiate power in a particular direction only. The directional pattern is a polar plot gives us the strength of radiated electromagnetic wave (in case of transmitting antenna) and strength of received electromagnetic wave (in case of receiving antenna) as a function of distance and angle. The directional pattern is affected by the shape and size of antenna, point of feed of RF signal etc.
- If the electric field E = 0.1 te–t ax and ∈ = 4∈0, then the displacement current crossing an area of 0.1 m2 at t = 0 will be—
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E = 0.1 t e– t ix
D = ∈r∈0 E
or D = ∈r∈0 0.1 t e– t ix
or D = 0.4 ∈0 [– te– t + e– t] ix
Dt = 0 = 0.4 ∈0 ix
Displacement current = 0.1 × 0.4 ∈0 ix
= 0.04 ∈0 ixCorrect Option: B
E = 0.1 t e– t ix
D = ∈r∈0 E
or D = ∈r∈0 0.1 t e– t ix
or D = 0.4 ∈0 [– te– t + e– t] ix
Dt = 0 = 0.4 ∈0 ix
Displacement current = 0.1 × 0.4 ∈0 ix
= 0.04 ∈0 ix