Electromagnetic theory miscellaneous Easy Questions and Answers

H = ∇ × A
∴ ∇ × H = ∇ × (∇ × A) = 0
∇. H = ∇. (∇ × A) = 0

H = ∇ × A
∴ ∇ × H = ∇ × (∇ × A) = 0
∇. H = ∇. (∇ × A) = 0

Given E = E₀ e^{j (ωt – βz)} [ax + ay]
[As only space quadrature and no time quadrature]
Hence the polarization is linear.

Given E = E₀ e^{j (ωt – βz)} [ax + ay]
[As only space quadrature and no time quadrature]
Hence the polarization is linear.

On comparing, given equation
γ = 0.1 π + j 0.2 π with
standard equation γ = α + jβ
β = 0.2 π
Now,

λ =	2∏	=	2∏	= 10 m
	β		.2∏

On comparing, given equation
γ = 0.1 π + j 0.2 π with
standard equation γ = α + jβ
β = 0.2 π
Now,

λ =	2∏	=	2∏	= 10 m
	β		.2∏

Electromagnetic theory miscellaneous

2	R₀
3

3	R₀
2