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A transmission line of characteristic impedance Z0 = 50 ohms, phase velocity vP = 2 × 108 m/s, and length I = 1 m is terminated by a load ZL = (30 – j 40) ohms. The input impedance of the line for a frequency of 100 MHz will be—
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- (30 + j 40) ohms
- (30 – j 40) ohms
- (50 + j 40) ohms
- (50 – j 40) ohms
Correct Option: B
VP = f λ
Therefore λ = VP/ f
= 2 × 108/ 100 × 106
= 2 m
Since length of the line is half wave length i.e.
| I = | = | = 1 | ||
| 2 | 2 |
Therefore, Zin = ZL
or Zin = (30 – j40) ohms.
