Electromagnetic theory miscellaneous
- A 50 Ω lossless T.L. has a pure reactance of j 100 Ω as its load. The VSWR in the live is—
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Reflection coefficient of the line,
Γ = ZL – Z0 ZL + Z0 = j 100 – 50 = 2j – 1 j 100 + 50 2j + 1
and|Γ| = √(2)² + (-1)² = √5 = 1 √(2)² + (1)² √5
(˙.˙ we are interested in magnitude only)
Now,VSWR = Γ + 1 = 1 + 1 = 2 = ∞ Γ – 1 1 – 1 0 Correct Option: B
Reflection coefficient of the line,
Γ = ZL – Z0 ZL + Z0 = j 100 – 50 = 2j – 1 j 100 + 50 2j + 1
and|Γ| = √(2)² + (-1)² = √5 = 1 √(2)² + (1)² √5
(˙.˙ we are interested in magnitude only)
Now,VSWR = Γ + 1 = 1 + 1 = 2 = ∞ Γ – 1 1 – 1 0