Theory of Machines Miscellaneous


Theory of Machines Miscellaneous

  1. The input link O2P of a four bar linkage is rotated at 2 rad/s in counter clockwise direction as shown below. The angular velocity of the coupler PQ in rad/s, at an instant when ∠O4O2P = 180°, is

    PQ = Q4Q = √2a
    O2P = O2O4 = a









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    When ∠O4O2 P = 180°

    Now,
    ω3
    =
    I12I23
    =
    a
    ω2I12I232a

    ω3
    =
    1
    22

    ω3 = 1 rad/s

    Correct Option: C


    When ∠O4O2 P = 180°

    Now,
    ω3
    =
    I12I23
    =
    a
    ω2I12I232a

    ω3
    =
    1
    22

    ω3 = 1 rad/s


  1. In a four-bar linkage, S denotes the shortest link length, L is the longest link length, P and Q are the lengths of other two links. At least one of the three moving links will rotate by 360° if









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    According to Grashoff’s Criteria.
    S + L ≤ P + Q

    Correct Option: A

    According to Grashoff’s Criteria.
    S + L ≤ P + Q



  1. For a mechanism shown below, the mechanical advantage for the given configuration is









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    Mechanical advantage =
    Load (output force)
    Effort (input force)

    For a four bar linkage in toggle position, effort = 0
    ∴  Mechanical Advantage = ∞

    Correct Option: A

    Mechanical advantage =
    Load (output force)
    Effort (input force)

    For a four bar linkage in toggle position, effort = 0
    ∴  Mechanical Advantage = ∞


  1. In a certain slider-crank mechanism, lengths of crank and connecting rod are equal. If the crank rotates with a uniform angular speed of 14 rad/s and the crank length is 300 mm, the maximum acceleration of the slider (in m/s2) is _________.









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    amax = 2rω²
    (where θ = 0) i.e at Inner dead centre
    = 2 × 0.3 × 14²
    amax = 117.6 m/s²

    Correct Option: C

    amax = 2rω²
    (where θ = 0) i.e at Inner dead centre
    = 2 × 0.3 × 14²
    amax = 117.6 m/s²



  1. A slider-crank mechanism with crank radius 60 mm and connecting rod length 240 mm is shown in figure. The crank is rotating with a uniform angular speed of 10 rad/s, counter clockwise. For the given configuration, the speed (in m/s) of the slider is _______.









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    L = 240 mm
    r = 60 mm

    n =
    L
    = 4
    r

    ω = 10 rad/s
    cosθ =
    sinθ
    n

    θ = tan−1(4) = 75.96°
    ∴  VS = ωrsinθ +
    sin2θ
    2n

    ∴  VS = 10 × 0.06sin75.96° +
    sin151.92°
    2 × 4

    = 0.6 × 1.0288
    = 0.6 m/s

    Correct Option: A


    L = 240 mm
    r = 60 mm

    n =
    L
    = 4
    r

    ω = 10 rad/s
    cosθ =
    sinθ
    n

    θ = tan−1(4) = 75.96°
    ∴  VS = ωrsinθ +
    sin2θ
    2n

    ∴  VS = 10 × 0.06sin75.96° +
    sin151.92°
    2 × 4

    = 0.6 × 1.0288
    = 0.6 m/s