Power electronics and drives miscellaneous
- In the circuit shown below what is the output voltage (Vout) in Volts if a silicon transistor Q and an ideal op-amp are used?
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I = I, e I = I0e VRE / VT , I = I0e -V0 / VT-V0 = VT ln I = VT ln I3ms I0 Is
V0 = - 0.7
RL = √Rs² + Xs² = √4² + 3² = 5Correct Option: B
I = I, e I = I0e VRE / VT , I = I0e -V0 / VT-V0 = VT ln I = VT ln I3ms I0 Is
V0 = - 0.7
RL = √Rs² + Xs² = √4² + 3² = 5
- A single-phase voltage source inverter shown in figure is feeding power to a load. The triggering pulses of the devices are also shown in the figure.
If the load current is sinusoidal and is zero at 0, π, 2π...., the node voltage VAO has the waveform
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NA
Correct Option: D
NA
- A three-phase fully controlled bridge converter is fed through star-delta transformer as shown in the figure.
The converter is operated at a firing angle of 30°. Assuming the load current (I0) to be virtually constant at 1 p.u. and transformer to be an ideal one, the input phase current waveform is
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NA
Correct Option: B
NA
- A single-phase SCR based ac regulator is feeding power to a load consisting of 5 Ω resistance and 16 mH inductance. The input supply is 230 V, 50 Hz ac. The maximum firing angle at which the voltage across the device becomes zero all throughout and the rms value of current through SCR, under this operating condition, are
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Vs = 230V, 50Hz
R = 5Ω, L = 16mH
The maximum firing angle at which the volt across device becomes zero is the angle at which device trigger i.e. minimum firing angle to converter.α = φ = tan-1 XL = tan-1 ωL R R α = φ = tan-1 2π × 50 × 16 × 10-3 = 45.1° 5
The current flowing SCR is max at their angle ie. when α = φ, γ = πITrms = Vm = √2 × 230 2z 2 × √5² + 5.042
∴ ITrms = 22.9 ≈ 23 A
Correct Option: C
Vs = 230V, 50Hz
R = 5Ω, L = 16mH
The maximum firing angle at which the volt across device becomes zero is the angle at which device trigger i.e. minimum firing angle to converter.α = φ = tan-1 XL = tan-1 ωL R R α = φ = tan-1 2π × 50 × 16 × 10-3 = 45.1° 5
The current flowing SCR is max at their angle ie. when α = φ, γ = πITrms = Vm = √2 × 230 2z 2 × √5² + 5.042
∴ ITrms = 22.9 ≈ 23 A
- In dc-chopper, per unit ripple is maximum when duty cycle α is ______ .
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NA
Correct Option: A
NA