Power electronics and drives miscellaneous


Power electronics and drives miscellaneous

Power Electronics and Drives

  1. In the circuit shown in the figure, the maximum current in the main SCR can be (given I0 = 70.7) ______ A .









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    IPeak = Io + Vs = 70.7 + 200

    = 170.7 A

    Correct Option: A

    IPeak = Io + Vs = 70.7 + 200

    = 170.7 A


  1. The circuit in the figure shows zener regulated dc power supply. The zener diode is ideal. The minimum value of RL down to which the output voltage remain constant, is ______ Ω .









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    I =
    24 - 15
    =
    1
    A ; and VL = 15 V
    273

    ∴ RL =
    VL
    =
    15
    = 45 Ω
    I1 / 3

    Correct Option: C

    I =
    24 - 15
    =
    1
    A ; and VL = 15 V
    273

    ∴ RL =
    VL
    =
    15
    = 45 Ω
    I1 / 3



  1. A dc source of 100 V supplies a purely inductive load 0.1 H. The controller is a thyristor in series with the source and load. The latching current specified is 100 mA. The minimum width of the gating pulse to ensure thyristor turn ON is ______ s .









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    For an inductive load,

    V = L
    di
    =
    LI
    dtT

    ⇒ T =
    LI
    =
    0.1 × 100 × 10-3
    = 0.1 ms or 100 μs
    V100

    Correct Option: A

    For an inductive load,

    V = L
    di
    =
    LI
    dtT

    ⇒ T =
    LI
    =
    0.1 × 100 × 10-3
    = 0.1 ms or 100 μs
    V100


  1. If in a 3-phase, half-wave rectifier, if per phase input voltage is 200 V, then average output voltage is ______ V.









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    Since Vt = 200 V, therefore
    table>Vo =

    3 √2 Vph
    =
    3 √2 × 200
    = 233.91 Vπ3.1414

    Correct Option: A

    Since Vt = 200 V, therefore
    table>Vo =

    3 √2 Vph
    =
    3 √2 × 200
    = 233.91 Vπ3.1414



  1. In the circuit shown below what is the output voltage (Vout) in Volts if a silicon transistor Q and an ideal op-amp are used?










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    I = I, e I = I0e VRE / VT , I = I0e -V0 / VT

    -V0 = VT ln
    I
    = VT ln
    I3ms
    I0Is

    V0 = - 0.7
    RL = √Rs² + Xs² = √4² + 3² = 5

    Correct Option: B


    I = I, e I = I0e VRE / VT , I = I0e -V0 / VT

    -V0 = VT ln
    I
    = VT ln
    I3ms
    I0Is

    V0 = - 0.7
    RL = √Rs² + Xs² = √4² + 3² = 5