Profit and Loss
- If goods be purchased for $ 450 and one third sold at a loss of 10%. At what gain per cent should the remainder be sold so as to gain 20% on the whole transaction?
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Let the required gain % = y.
∴ 150 × 90 + 300 × (100 + y) = 450 × 120 100 100 100
Correct Option: B
Let the required gain % = y.
∴ 150 × 90 + 300 × (100 + y) = 450 × 120 100 100 100
⇒ 135 + 3 (100 + y ) = 540
⇒ 3 (100 + y) = 540 – 135 = 405∴ 100 + y = 405 = 135 3
⇒ y = 135 – 100 = 35%
Hence , required gain% is 35% .
- A shoe company sold 50 pairs of shoes on a day costing $ 189.50 each for $ 10,000. Then the profit obtained in $ is
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Given , C.P. of 1 pairs of shoes = $ 189.50
∴ C.P. of 50 pairs of shoes = $ (50 × 189.50) = $ 9475
Selling Price of 50 pairs of shoes = $ 10000
Required Gain = Selling Price of 50 pairs of shoes - Cost Price of 50 pairs of shoesCorrect Option: B
Given , C.P. of 1 pairs of shoes = $ 189.50
∴ C.P. of 50 pairs of shoes = $ (50 × 189.50) = $ 9475
Selling Price of 50 pairs of shoes = $ 10000
Required Gain = Selling Price of 50 pairs of shoes - Cost Price of 50 pairs of shoes
∴ Required Gain = $ (10000 – 9475)= $ 525
- Salim had to sell vegetables worth $ 5,750 for $ 4,500 due to heavy rainfall. What is the loss percentage that he has incurred?
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Here , Cost price of vegetables = $ 5,750
Selling price of vegetables = $ 4500
Loss = Cost price of vegetables - Selling price of vegetables = 5750 - 4500 = $ 1250Loss percent = Loss × 100 Cost price of vegetables
Correct Option: A
Here , Cost price of vegetables = $ 5,750
Selling price of vegetables = $ 4500
Loss = Cost price of vegetables - Selling price of vegetables = 5750 - 4500 = $ 1250Loss percent = Loss × 100 Cost price of vegetables Loss percent = 1250 × 100 5750 Loss percent = 125000 = 21.74% 5750
- If I purchased 11 books for $ 100 and sold 10 books for $ 110, the percentage of profit per book sold is
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If a articles are bought for $ p
and b articles are sold for $ q,
thenGain% = 
qa - pb 
× 100 pb Gain% = 11 × 110 - 10 × 100 × 100 10 × 100 Gain % = 1210 - 1000 × 100 = 21% 1000
Second method to solve this question :
Here, a = 11, p = 100 and b = 10, y = 110Gain% = aq - bp × 100% bp
Correct Option: D
If a articles are bought for $ p
and b articles are sold for $ q,
thenGain% = qa - pb × 100 pb Gain% = 11 × 110 - 10 × 100 × 100 10 × 100 Gain % = 1210 - 1000 × 100 = 21% 1000
Second method to solve this question :
Here, a = 11, p = 100 and b = 10, y = 110Gain% = aq - bp × 100% bp Gain% = 11 × 110 - 10 × 100 × 100 10 × 100 Gain% = 1210 - 1000 × 100% = 21% 1000
- A man buys a certain number of oranges at 20 for 60 and an equal number at 30 for $ 60. He mixes them and sells them at 25 for $ 60. What is gain or loss percent?
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Let the man buy 60 oranges (LCM of 20 and 30) of each kind.
CP of the 60 oranges of the first kind = 60 × 60 = $ 180 20 CP of 60 oranges of second kind = 60 × 60 = $ 120 30
Total CP of 120 oranges = (180 + 120) = $ 300
Correct Option: B
Let the man buy 60 oranges (LCM of 20 and 30) of each kind.
CP of the 60 oranges of the first kind = 60 × 60 = $ 180 20 CP of 60 oranges of second kind = 60 × 60 = $ 120 30
Total CP of 120 oranges = (180 + 120) = $ 300SP of 120 oranges = 60 × 120 = $ 288 25
Loss = CP of 120 oranges - SP of 120 oranges = $ (300 – 288) = $ 12∴ Loss Percent = 12 × 100 = 4% 300
