Profit and Loss
- If the cost price of 50 oranges is equal to the selling price of 40 oranges, then the profit per cent is
-
View Hint View Answer Discuss in Forum
Let the C.P. of one orange = 1
∴ C.P. of 40 oranges = $ 40
and S.P. of 40 oranges = $ 50
∴ Profit = (50 – 40) = $ 10∴ Profit % = Profit × 100 C.P. of 40 oranges Profit % = 10 × 100 = 25% 40
Second method to solve this question :
Here, p = 50, q = 40Profit % = p - q × 100 q
Correct Option: D
Let the C.P. of one orange = 1
∴ C.P. of 40 oranges = $ 40
and S.P. of 40 oranges = $ 50
∴ Profit = (50 – 40) = $ 10∴ Profit % = Profit × 100 C.P. of 40 oranges Profit % = 10 × 100 = 25% 40
Second method to solve this question :
Here, p = 50, q = 40Profit % = p - q × 100 q Profit % = 50 - 40 × 100 = 25% 40
- A person sells 400 mangoes at the cost price of 320 mangoes. His percentage of loss is
-
View Hint View Answer Discuss in Forum
Let the C.P. of one mango be Rs. 1.
then , C.P. of 400 mangoes = Rs. 400.
S.P. of 400 mangoes = Rs. 320.
Loss = 400 - 320 = Rs. 80∴ Loss percent = Loss × 100 C.P. of 400 mangoes
Correct Option: C
Let the C.P. of one mango be Rs. 1.
then , C.P. of 400 mangoes = Rs. 400.
S.P. of 400 mangoes = Rs. 320.
Loss = 400 - 320 = Rs. 80∴ Loss percent = Loss × 100 C.P. of 400 mangoes Loss percent = 80 × 100 = 20% 400
- The cost price of 18 articles is equal to the selling price of 15 articles. The gain percent is :
-
View Hint View Answer Discuss in Forum
Let Cost price of each article is ₹ 1 .
Cost price of 15 articles = ₹ 15
Selling price of 15 articles = ₹ 18
Gain = 18 - 15 = ₹ 3Gain % = Gain × 100 Cost price of 15 articles Gain % = 3 × 100 = 20 % 15
Second method to solve this question :
Here, p = 18, q = 15Gain% = p - q × 100 q
Correct Option: B
Let Cost price of each article is ₹ 1 .
Cost price of 15 articles = ₹ 15
Selling price of 15 articles = ₹ 18
Gain = 18 - 15 = ₹ 3Gain % = Gain × 100 Cost price of 15 articles Gain % = 3 × 100 = 20 % 15
Second method to solve this question :
Here, p = 18, q = 15Gain% = p - q × 100 q Gain % = 18 - 15 × 100 15 Gain % = 3 × 100 = 20 % 15
- If the cost price of 15 tables be equal to the selling price of 20 tables, the loss per cent is :
-
View Hint View Answer Discuss in Forum
Let the cost price of one table = y
∴ Cost price of 15 tables = 15y and cost price of 20 tables = 20y
According to the question ,
Selling price of 20 tables = cost price of 15 tables = 15y
∴ Loss = 20y – 15y = 5y∴ Loss% = 5y × 100 = 25% 20y
Second method to solve this question :
Here, p = 15, q = 20Loss% = p - q × 100 q
Correct Option: C
Let the cost price of one table = y
∴ Cost price of 15 tables = 15y and cost price of 20 tables = 20y
According to the question ,
Selling price of 20 tables = cost price of 15 tables = 15y
∴ Loss = 20y – 15y = 5y∴ Loss% = 5y × 100 = 25% 20y
Second method to solve this question :
Here, p = 15, q = 20Loss% = p - q × 100 q Loss% = 15 - 20 × 100 20 Loss% = -5 × 100 = –25% (–ve sign shows loss) 20
Hence , Loss% = 25%
- The selling price of 5 articles is the same as the cost price of 3 articles. The gain or loss per cent is :
-
View Hint View Answer Discuss in Forum
According to question , we have
C.P. of 3 articles = S.P. of 5 articles⇒ C.P. = 5 S.P. 3
Loss = S.P. - C.P. = 5 - 3 = $ 2Loss% = Loss × 100 5
Loss% = 2 × 20 = 40%
Second method to solve this question :
Here, p = 3, q = 5Loss % = p - q × 100 q
Correct Option: D
According to question , we have
C.P. of 3 articles = S.P. of 5 articles⇒ C.P. = 5 S.P. 3
Loss = S.P. - C.P. = 5 - 3 = $ 2Loss% = Loss × 100 5
Loss% = 2 × 20 = 40%
Second method to solve this question :
Here, p = 3, q = 5Loss % = p - q × 100 q Loss% = 3 - 5 × 100 = – 40% (–ve sign shows loss) 5
Loss% = 40%